Android fragments Popbackstack总是返回上一个调用

Android fragments Popbackstack总是返回上一个调用,android-fragments,fragmentmanager,fragmenttransaction,fragment-backstack,supportfragmentmanager,Android Fragments,Fragmentmanager,Fragmenttransaction,Fragment Backstack,Supportfragmentmanager,我有三个简单的片段:片段A,片段B,片段C 片段A->片段B: FragmentB fragment2 = new FragmentB (); FragmentManager fragmentManager = getActivity().getSupportFragmentManager(); FragmentTransaction fragmentTransaction = fragmentManager.beginTransaction(); fragmentTransaction.add

我有三个简单的片段:片段A,片段B,片段C

片段A->片段B:

FragmentB fragment2 = new FragmentB ();
FragmentManager fragmentManager = getActivity().getSupportFragmentManager();
FragmentTransaction fragmentTransaction = fragmentManager.beginTransaction();
fragmentTransaction.addToBackStack(null);
fragmentTransaction.replace(R.id.mainLayout, fragment2);
fragmentTransaction.commit();
片段B->片段C:

FragmentC fC= new FragmentC ();
FragmentManager fragmentManager =  getActivity().getSupportFragmentManager();
FragmentTransaction fragmentTransaction = fragmentManager.beginTransaction();
fragmentTransaction.replace(R.id.mainLayout, fC);
fragmentTransaction.addToBackStack("FragmentA");
fragmentTransaction.commit();
碎片C->碎片A:

getActivity().getSupportFragmentManager().popBackStack("FragmentA",0);
问题是我总是回到碎片B,尽管我的目标是回到碎片A。我错过了什么

FragmentManager fmManager = getFragmentManager();
if (fmManager.getBackStackEntryCount() > 0) { fmManager.popBackStack(fmManager.getBackStackEntryAt(fmManager.getBackStackEntryCount()-2).getId(), fmManager.POP_BACK_STACK_INCLUSIVE); }
这段代码的作用是检查是否有堆叠的片段。如果是,它将获取第一个桩号处的片段,即fragmentA,并返回到该片段。重要的是你知道碎片的位置