Android BLE RxKotlin

我正在尝试创建一个BLE服务，该服务将扫描设备，并使用rxKotlin创建一个observable，允许另一个类在找到设备时进行观察。我对如何创建允许另一个类订阅的observable感到困惑，到处都是教程。有人能给我一个如何做的指针或一个好的教程

发现设备的Bluetoothservice类回调

var foundDeviceObservable: Observable<BluetoothDevice> = Observable.create {  }

private val scanCallback = object : ScanCallback() {
    override fun onScanResult(callbackType: Int, result: ScanResult) {
        with(result.device) {
            var foundName = if (name == null) "N/A" else name
            foundDevice = BluetoothDevice(
                foundName,
                address,
                address,
                result.device.type.toString()
            )
            foundDeviceObservable.subscribe {
               //Update Observable value?
            }
        }
    }
}

class DeviceListViewModel(application: Application) : AndroidViewModel(application) {
    private val bluetoothService = BLEService()

    //Where I am trying to do logic with device
    fun getDeviceObservable(){
        bluetoothService.getDeviceObservable().subscribe{ it ->
        
    }
}

使用行为主体

//创建行为主体
var foundDeviceObservable:BehaviorSubject=BehaviorSubject（）
//调用onNext（）发送新找到的设备
foundDeviceObservable.onNext（foundDevice）
//您的逻辑是否使用foundDeviceObservable
foundDeviceObservable.subscribe（…）

谢谢！正因为如此，我才想出了解决办法，并睡了个好觉。然后在get函数中返回foundDeviceObservable。我将不得不研究更多的rxkotlin，我没有意识到行为主体是一条路要走。

var foundDeviceObservable: BehaviorSubject<BluetoothDevice> = BehaviorSubject.create()

private val scanCallback = object : ScanCallback() {
    override fun onScanResult(callbackType: Int, result: ScanResult) {
        with(result.device) {
            var foundName = if (name == null) "N/A" else name
            foundDevice = BluetoothDevice(
                foundName,
                address,
                address,
                result.device.type.toString()
            )
            foundDeviceObservable.onNext(foundDevice)
        }
    }
}