多个edittext，在android中只有一个用于计算的textwatchers

我将从第一个

EditText

中获取一个值，从第二个

EditText

中获取一个值。这两个值都将被计算出来，并在第三个

EditText

中显示结果，而第三个

EditText

在android中只使用一个

TextWatcher

。 请帮帮我谢谢你

public class TextWatcher_Activity extends Activity {
    private EditText passwordEditText, passwordEditText1, passwordEditText2;
    private TextView textView;
    private View view;

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_textwatcher);

        /* Initializing views */
        passwordEditText = (EditText) findViewById(R.id.password);
        textView = (TextView) findViewById(R.id.passwordHint);
        textView.setVisibility(View.GONE);

        passwordEditText1 = (EditText) findViewById(R.id.password1);
        passwordEditText2 = (EditText) findViewById(R.id.password2);

 passwordEditText.addTextChangedListener(passwordWatcher);
        passwordEditText1.addTextChangedListener(passwordWatcher);
        passwordEditText2.addTextChangedListener(passwordWatcher);  
}
     private final TextWatcher passwordWatcher = new TextWatcher() {
            public void beforeTextChanged(CharSequence s, int start, int count, int after) {

            }

            public void onTextChanged(CharSequence s, int start, int before, int count) {
                textView.setVisibility(View.VISIBLE);
            }

            public void afterTextChanged(Editable s) {


               *//* if (s.hashCode() == passwordEditText.getText().hashCode()) {
                    //Do else something with input.
                } else if (s.hashCode() == passwordEditText1.getText().hashCode()) {
                    //Do something else useful with input.
                }*//*

                switch (view.getId()) {
                    case R.id.password:
                        //doStuff(1);
                        if (s.length() == 0) {
                            textView.setVisibility(View.GONE);
                        } else {
                            textView.setText("You have entered : " + passwordEditText.getText());
                        }
                        break;
                    case R.id.password1:
                        //doStuff(2);
                        if (s.length() == 0) {
                            textView.setVisibility(View.GONE);
                        } else {
                            textView.setText("You have entered : " + passwordEditText1.getText());
                        }
                        break;
                    case R.id.password2:
                        if (s.length() == 0) {
                            textView.setVisibility(View.GONE);
                        } else {
                            textView.setText("You have entered : " + passwordEditText2.getText());
                        }
                        break;
                }
            }
        };

---

您可以使用此方法并调整代码

private void calculate(EditText editText1, EditText editText2, final EditText editText3) {
        final int[] value1 = {0};
        final int[] value2 = {0};
        final int[] total = {0};
        editText1.addTextChangedListener(new TextWatcher() {
            @Override
            public void beforeTextChanged(CharSequence s, int start, int count, int after) {}

            @Override
            public void onTextChanged(CharSequence s, int start, int before, int count) {
                value1[0] = Integer.parseInt(s.toString());
                total[0] = value1[0] + value2[0];
                editText3.setText(total[0]);
            }

            @Override
            public void afterTextChanged(Editable s) {}
        });
        editText2.addTextChangedListener(new TextWatcher() {
            @Override
            public void beforeTextChanged(CharSequence s, int start, int count, int after) {}

            @Override
            public void onTextChanged(CharSequence s, int start, int before, int count) {
                value2[0] = Integer.parseInt(s.toString());
                total[0] = value1[0] + value2[0];
                editText3.setText(total[0]);
            }

            @Override
            public void afterTextChanged(Editable s) {}
        });
    }

---

editText3总共有editText1+editText2，您尝试了什么？我在使用此函数时出错，请告诉我如何调用activitycall它您将如何调用任何其他方法，只需传递EditTextEG

calculate（editText1，editText2，editText3）