Android kSOAP2输出/org.xmlpull.v1.xmlpullparserexception预期开始标记
我有一个标准的代码来调用Android kSOAP2输出/org.xmlpull.v1.xmlpullparserexception预期开始标记,android,android-ksoap2,Android,Android Ksoap2,我有一个标准的代码来调用.net webservice 我在第行获得异常“org.xmlpull.v1.xmlpullparserexception预期开始标记” transportSE.call(SOAP_ACTION,soapSerializationEnvelope); 但是,如果我从.netcode调用相同的Web服务,我会得到结构良好的适当输出 主要似乎是从kSOAP2中,它得到了一个明确的输出,但是当它进一步解析w.r.t SoapPrimitive对象时,它失败了 那么,是否有其
.net webservice
我在第行获得异常“org.xmlpull.v1.xmlpullparserexception预期开始标记”
transportSE.call(SOAP_ACTION,soapSerializationEnvelope);
但是,如果我从.netcode
调用相同的Web服务,我会得到结构良好的适当输出
主要似乎是从kSOAP2
中,它得到了一个明确的输出,但是当它进一步解析w.r.t SoapPrimitive对象时,它失败了
那么,是否有其他方法可以查看接收到的实际输出(实际的soap信封),然后自己对其进行适当的解析。我正在调查一个类似的问题。无意中发现了这一评论 当我使用SoapEnvelope.VER11时,它工作正常,但当我使用 SoapEnvelope.VER12,它给了我一个错误: “org.xmlpull.v1.XmlPullParserException:应为:开始标记”
也许我们在soap版本方面存在兼容性问题。此外,连接到点网服务时,您可能需要设置
envelope.dotNet=true代码>。。但是你可能已经做到了现在我已经解决了我原来的问题,点击这个
我发现ksoap2无法解析响应。。。特别是org.kxml2.io.KXmlParser.require(类型、命名空间、名称)引发了以下异常
WARN/System.err(2330): org.xmlpull.v1.XmlPullParserException: expected: START_TAG {http://www.w3.org/2001/12/soap-envelope}Envelope (position:START_TAG <h1>@1:4 in java.io.InputStreamReader@47ff3050)
WARN/System.err(2330):org.xmlpull.v1.XmlPullParserException:应为:开始标签{http://www.w3.org/2001/12/soap-envelope}信封(位置:java.io中的START_标记@1:4)。InputStreamReader@47ff3050)
请注意h1标记。来自404未找到的。。。因此,是的,请注意您的响应可能来自网站,而不是您的web服务:)
希望有一天能帮助别人我也犯了同样的错误,我的例外是“位置:开始标记@2:7”
但我已经修复了,因为我以错误的方式命名了一个参数,该名称必须与XSD上指定的完全相同
SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);
request.addProperty("arg0_java_lang_String", "Club");
在addProperty方法中,我使用了一个错误的参数名。我得到了这个开始标记异常,但在我的情况下,这是因为
METHOD_NAME="";
NAMESPACE ="";
SOAP_ACTION ="";
URL ="";
这是不对的
现在,如何找出这些参数的正确值,您可以
确保Web服务的url可访问后,使用以下代码查看变量urlc.getResponseCode()
获取响应代码,同时将ip从本地主机、固定、外部更改为10.0.2.2
public static boolean isNetworkAvailable() {
//http://stackoverflow.com/questions/1560788/how-to-check-internet-access-on-android-inetaddress-never-timeouts/4009133#comment24565402_4009133
/* ConnectivityManager cm =
(ConnectivityManager) _context.getSystemService(Context.CONNECTIVITY_SERVICE);
NetworkInfo netInfo = cm.getActiveNetworkInfo();
if (netInfo != null && netInfo.isConnected()) {//netInfo.isConnectedOrConnecting()
return true;
}
return false;*/
//http://stackoverflow.com/questions/5474089/how-to-check-currently-internet-connection-is-available-or-not-in-android?rq=1
boolean connected = false;
ConnectivityManager connectivityManager = (ConnectivityManager)_context.getSystemService(Context.CONNECTIVITY_SERVICE);
if(connectivityManager.getNetworkInfo(ConnectivityManager.TYPE_MOBILE).getState() == NetworkInfo.State.CONNECTED ||
connectivityManager.getNetworkInfo(ConnectivityManager.TYPE_WIFI).getState() == NetworkInfo.State.CONNECTED) {
//we are connected to a network
connected=true;
return connected;
}
else
{
connected=false;
return false;
}
}
public static boolean hasActiveInternetConnection() {
if (isNetworkAvailable()) {
try {
//String url = "http://www.google.com",
String url = "http://10.0.2.2:8089/UNIV_AXIS_DYN_WEB/services/ServiceMethods?wsdl",
proxy = "proxy.rss.jo",
port= "8080";
URL server = new URL(url);
Properties systemProperties = System.getProperties();
/*systemProperties.setProperty("http.prosyHost",proxy);
systemProperties.setProperty("http.prosyHost",port);*/
HttpURLConnection urlc = (HttpURLConnection) (server.openConnection());
urlc.setRequestProperty("User-Agent", "Test");
urlc.setRequestProperty("Connection", "close");
urlc.setConnectTimeout(500);
urlc.connect();
System.out.println(urlc.getResponseCode());
return (urlc.getResponseCode() == 200);
} catch (IOException e) {
Log.e(LOG_TAG, "Error checking internet connection", e);
return false;
}
} else {
Log.d(LOG_TAG, "No network available!");
return false;
}
}
对我来说,我得到的提示是“不是下面缺少的字符s”
尝试调用服务方法登录时发生异常
org.apache.axis2.AxisFault:命名空间不匹配要求http://services.univ.rss 建立http://service.univ.rss
日志tomcat等的其余部分
at org.apache.axis2.rpc.receivers.RPCUtil.invokeServiceClass(RPCUtil.java:190)
at org.apache.axis2.rpc.receivers.RPCMessageReceiver.invokeBusinessLogic(RPCMessageReceiver.java:117)
at org.apache.axis2.receivers.AbstractInOutMessageReceiver.invokeBusinessLogic(AbstractInOutMessageReceiver.java:40)
at org.apache.axis2.receivers.AbstractMessageReceiver.receive(AbstractMessageReceiver.java:114)
at org.apache.axis2.engine.AxisEngine.receive(AxisEngine.java:181)
at org.apache.axis2.transport.http.HTTPTransportUtils.processHTTPPostRequest(HTTPTransportUtils.java:172)
at org.apache.axis2.transport.http.AxisServlet.doPost(AxisServlet.java:146)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:727)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:820)
at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:290)
at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:206)
at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:233)
at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:191)
at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:127)
at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:102)
at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:109)
at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:298)
at org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:852)
at org.apache.coyote.http11.Http11Protocol$Http11ConnectionHandler.process(Http11Protocol.java:588)
at org.apache.tomcat.util.net.JIoEndpoint$Worker.run(JIoEndpoint.java:489)
at java.lang.Thread.run(Unknown Source)
是的,在跟踪LogCat之后,我没有检查tomcat服务器日志eve如果服务测试成功,您应该在每次更改测试中监视所有日志,我甚至一开始忘记启动数据库服务,所以请小心:)
Soap调用
public SoapObject SoapCall(Vector<PropertyInfo> propertyInfo)
{
Integer parametersSize = propertyInfo.size();
//Initialize soap request + add parameters
SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);
for(int i=0;i<parametersSize;i++)
{
request.addProperty(propertyInfo.get(i));
}
SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
//envelope.dotNet = false; if service of type asmx .NET
envelope.setOutputSoapObject(request);
Log.d("App Log c ","c");
HttpTransportSE androidHttpTransport = new HttpTransportSE(URL);
try {
System.out.println(androidHttpTransport.getPort());
// Make the soap call.
//this is the actual part that will call the webservice
androidHttpTransport.call(SOAP_ACTION, envelope);
SoapPrimitive response = (SoapPrimitive)envelope.getResponse();
//Log.i("App Log 1 ", response.toString());
} catch (Exception e) {
e.printStackTrace();
}
// Get the SoapResult from the envelope body.
SoapObject result = (SoapObject)envelope.bodyIn;
Log.i("App Log 2 ", result.toString());
Log.i("App Log 2 ", result.getProperty(0).toString());
return result;
}
public SoapObject SoapCall(Vector propertyInfo)
{
整数参数ssize=propertyInfo.size();
//初始化soap请求+添加参数
SoapObject请求=新的SoapObject(名称空间、方法名称);
对于(int i=0;iis)您的.NET Web服务返回一个基元类型?如果不是,那么您应该尝试使用SoapObject代替SoapPrimitive类型。它返回一个字符串,所以是的……SoapObject应该在这里,但这不是我面临的问题。它在transportSE.call(SOAP\u操作,soapSerializationEnvelope)上卡住了;那么,我如何查看实际/原始soapenvelope…以进行验证,因为在调用方法中,解析异常发生时,我看到调用“transportSE.requestDump”时信封完全符合要求,调用“transportSE.responseDump”时获得空字符串,调用“soapSerializationEnvelope.bodyIn”时获得空o/p…任何输入的家伙…我真的卡住了…我的意思是我看不出有什么不同的事情要做,主要是其他非移动客户端能够从相同的给定web服务获取所需的响应
public SoapObject SoapCall(Vector<PropertyInfo> propertyInfo)
{
Integer parametersSize = propertyInfo.size();
//Initialize soap request + add parameters
SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);
for(int i=0;i<parametersSize;i++)
{
request.addProperty(propertyInfo.get(i));
}
SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER11);
//envelope.dotNet = false; if service of type asmx .NET
envelope.setOutputSoapObject(request);
Log.d("App Log c ","c");
HttpTransportSE androidHttpTransport = new HttpTransportSE(URL);
try {
System.out.println(androidHttpTransport.getPort());
// Make the soap call.
//this is the actual part that will call the webservice
androidHttpTransport.call(SOAP_ACTION, envelope);
SoapPrimitive response = (SoapPrimitive)envelope.getResponse();
//Log.i("App Log 1 ", response.toString());
} catch (Exception e) {
e.printStackTrace();
}
// Get the SoapResult from the envelope body.
SoapObject result = (SoapObject)envelope.bodyIn;
Log.i("App Log 2 ", result.toString());
Log.i("App Log 2 ", result.getProperty(0).toString());
return result;
}
Vector<PropertyInfo> vectorProperyInfo = new Vector<PropertyInfo>();
PropertyInfo userProp = new PropertyInfo();
userProp.setName("userName");
userProp.setValue(username);
userProp.setType(String.class);
vectorProperyInfo.addElement(userProp);
PropertyInfo passProp = new PropertyInfo();
passProp.setName("pass");
passProp.setValue(password);
passProp.setType(String.class);
vectorProperyInfo.addElement(passProp);
SoapObject result = soapUtil.SoapCall(vectorProperyInfo);
if (result != null && result.getProperty(0).toString().equals("1")) {
return "LOGIN_SUCCESS";// for a student
}