Android将JSONObject转换为HashMap，并使用SimpleAdapter在ListView中显示

我尝试搜索将JSONObject转换为HashMap，但大多数结果都是针对Java而不是Android的。因此，我希望有人可以分享，如果你有这样做的经验之前

listview_与_simpleAdapter_和_hashmap.java

JSON也运行良好。格式与ListView数据->ID和名称完全相同

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因此，我的问题是如何使用simpledapter_和hashmap.java将omg.php中的JSONObject转换为listview_？我只需要一个简单的例子。

您可以这样做：

ListView listView = (ListView) findViewById(R.id.listView);

// ...

@Override
public void onResponse(JSONObject response) {
    List<HashMap<String, String>> list = new ArrayList<HashMap<String, String>>();

    try {
        Iterator<String> iterator = response.keys();

        while (iterator.hasNext()) {
            String key = iterator.next();
            String value = response.getString(key);

            HashMap<String, String> map = new HashMap<>();
            map.put(KEY_ID, key);
            map.put(KEY_NAME, value);

            list.add(map);
        }
    } catch (JSONException e) {
        e.printStackTrace();
    }

    if(list.size() > 0) {
        String[] from = {KEY_ID, KEY_NAME};
        int[] to = {R.id.text_id, R.id.text_name};

        SimpleAdapter adapter = new SimpleAdapter(MainActivity.this, list,
            R.layout.list_item, from, to);

        listView.setAdapter(adapter);
    }
}

---

你可以这样做：

ListView listView = (ListView) findViewById(R.id.listView);

// ...

@Override
public void onResponse(JSONObject response) {
    List<HashMap<String, String>> list = new ArrayList<HashMap<String, String>>();

    try {
        Iterator<String> iterator = response.keys();

        while (iterator.hasNext()) {
            String key = iterator.next();
            String value = response.getString(key);

            HashMap<String, String> map = new HashMap<>();
            map.put(KEY_ID, key);
            map.put(KEY_NAME, value);

            list.add(map);
        }
    } catch (JSONException e) {
        e.printStackTrace();
    }

    if(list.size() > 0) {
        String[] from = {KEY_ID, KEY_NAME};
        int[] to = {R.id.text_id, R.id.text_name};

        SimpleAdapter adapter = new SimpleAdapter(MainActivity.this, list,
            R.layout.list_item, from, to);

        listView.setAdapter(adapter);
    }
}

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尝试以下代码将Jsonobject转换为hashmap

 Map<String, String> params = new HashMap<String, String>();
                try
                {

                   Iterator<?> keys = jsonObject.keys();

                    while (keys.hasNext())
                    {
                        String key = (String) keys.next();
                        String value = jsonObject.getString(key);
                        params.put(key, value);

                    }


                }
                catch (Exception xx)
                {
                    xx.toString();
                }

---

尝试以下代码将Jsonobject转换为hashmap

 Map<String, String> params = new HashMap<String, String>();
                try
                {

                   Iterator<?> keys = jsonObject.keys();

                    while (keys.hasNext())
                    {
                        String key = (String) keys.next();
                        String value = jsonObject.getString(key);
                        params.put(key, value);

                    }


                }
                catch (Exception xx)
                {
                    xx.toString();
                }

---

试试这个答案@codephillip那甚至不是安卓-试试这个答案@codephillip那甚至不是安卓--

 Map<String, String> params = new HashMap<String, String>();
                try
                {

                   Iterator<?> keys = jsonObject.keys();

                    while (keys.hasNext())
                    {
                        String key = (String) keys.next();
                        String value = jsonObject.getString(key);
                        params.put(key, value);

                    }


                }
                catch (Exception xx)
                {
                    xx.toString();
                }