连接新的Android项目与解析服务器示例和解析仪表板(本地)
我正在尝试将一个新的android项目与解析服务器示例(本地)连接起来,并用解析仪表板显示它。我已经成功地将parse server示例与parse dashboard…(通过在parse server示例/index.js和parse dashboard/parse dashboard config.json中更改appId和masterKey)链接。我已经安装了mongodb和所有东西(mongodb、解析服务器示例和解析仪表板工作得非常好) 但现在,当我试图在android项目中初始化parse服务器时,它在本地parse中不会创建任何东西(类)。谢谢我的代码 清单文件连接新的Android项目与解析服务器示例和解析仪表板(本地),android,mongodb,parse-platform,parse-server,Android,Mongodb,Parse Platform,Parse Server,我正在尝试将一个新的android项目与解析服务器示例(本地)连接起来,并用解析仪表板显示它。我已经成功地将parse server示例与parse dashboard…(通过在parse server示例/index.js和parse dashboard/parse dashboard config.json中更改appId和masterKey)链接。我已经安装了mongodb和所有东西(mongodb、解析服务器示例和解析仪表板工作得非常好) 但现在,当我试图在android项目中初始化pa
<?xml version="1.0" encoding="utf-8"?>
<!--
~ Copyright (c) 2015-present, Parse, LLC.
~ All rights reserved.
~
~ This source code is licensed under the BSD-style license found in the
~ LICENSE file in the root directory of this source tree. An additional grant
~ of patent rights can be found in the PATENTS file in the same directory.
-->
<manifest xmlns:android="http://schemas.android.com/apk/res/android"
package="com.parse.starter" >
<uses-permission android:name="android.permission.INTERNET" />
<uses-permission android:name="android.permission.ACCESS_NETWORK_STATE" />
<application
android:name=".StarterApplication"
android:allowBackup="true"
android:icon="@mipmap/ic_launcher"
android:label="@string/app_name"
android:theme="@style/AppTheme" >
<meta-data
android:name="com.parse.APPLICATION_ID"
android:value="@string/parse_app_id" />
<meta-data
android:name="com.parse.CLIENT_KEY"
android:value="@string/parse_client_key" />
<activity
android:name=".MainActivity"
android:label="@string/app_name" >
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
</activity>
</application>
</manifest>
MainActivity.java
package com.parse.starter;
import android.os.Bundle;
import android.support.v7.app.ActionBarActivity;
import android.support.v7.app.AppCompatActivity;
import android.view.Menu;
import android.view.MenuItem;
import com.parse.Parse;
import com.parse.ParseAnalytics;
import com.parse.ParseObject;
public class MainActivity extends AppCompatActivity {
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
ParseAnalytics.trackAppOpenedInBackground(getIntent());
}
@Override
public boolean onCreateOptionsMenu(Menu menu) {
// Inflate the menu; this adds items to the action bar if it is present.
getMenuInflater().inflate(R.menu.menu_main, menu);
return true;
}
@Override
public boolean onOptionsItemSelected(MenuItem item) {
// Handle action bar item clicks here. The action bar will
// automatically handle clicks on the Home/Up button, so long
// as you specify a parent activity in AndroidManifest.xml.
int id = item.getItemId();
//noinspection SimplifiableIfStatement
if (id == R.id.action_settings) {
return true;
}
return super.onOptionsItemSelected(item);
}
}
StarterApplication.java
package com.parse.starter;
import android.app.Application;
import com.parse.Parse;
import com.parse.ParseACL;
import com.parse.ParseObject;
import com.parse.ParseUser;
public class StarterApplication extends Application {
@Override
public void onCreate() {
super.onCreate();
// Enable Local Datastore.
Parse.enableLocalDatastore(this);
// Add your initialization code here
//Parse.initialize(this);
Parse.initialize(new Parse.Configuration.Builder(getApplicationContext())
.applicationId("@string/parse_app_id")
.clientKey("@string/parse_client_key")
.server("http://localhost:1337/parse/") // '/' important after 'parse'
.build());
ParseObject testObject = new ParseObject("TestObject");
testObject.put("foo", "bar");
testObject.saveInBackground();
ParseUser.enableAutomaticUser();
ParseACL defaultACL = new ParseACL();
// Optionally enable public read access.
// defaultACL.setPublicReadAccess(true);
ParseACL.setDefaultACL(defaultACL, true);
}
}
我还尝试将对象的创建放在主活动中
MainActivity.java
public class MainActivity extends AppCompatActivity {
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
ParseAnalytics.trackAppOpenedInBackground(getIntent());
ParseObject testObject = new ParseObject("TestObject");
testObject.put("foo", "bar");
testObject.saveInBackground();
}
为什么代码中有localhost?Localhost意味着请求在本地设备上运行,您可以在服务器内部使用它,但不能在客户端设备上使用。尝试将服务器/计算机的一些IP地址放在那里
.server("http://localhost:1337/parse/")
在初始化方法中,使用.server(API_地址),API地址由解析服务提供者提供。e、 g.back4app调用它的API地址谢谢..答案..解决了!!你对ParseUser.getCurrentUser()做了什么。文档中说使用request.user,但什么是request object.what不是localhost,而是写远程设备可以远程访问的服务器的IP地址,例如10.0.0.3或192.168.1.1,您的IP地址看起来会不同。请确保删除Android清单文件中的以下行,这是因为您在Starter Application.java中使用了自定义配置
.server("http://localhost:1337/parse/")