Android 不同峰值之间的峰值
我试图得到这两个峰值,一旦我从我的文本文件读取。我已经定义了两个字符串来比较两个值以找到峰值,但我认为我的if(y_0>MP)语句在找到两个峰值方面不正确。我该怎么办Android 不同峰值之间的峰值,android,android-intent,android-activity,Android,Android Intent,Android Activity,我试图得到这两个峰值,一旦我从我的文本文件读取。我已经定义了两个字符串来比较两个值以找到峰值,但我认为我的if(y_0>MP)语句在找到两个峰值方面不正确。我该怎么办 //Read data. Recall = (Button) findViewById(R.id.Recall); Recall.setOnClickListener(new View.OnClickListener() { StringBuilder stringBuilder;
//Read data.
Recall = (Button) findViewById(R.id.Recall);
Recall.setOnClickListener(new View.OnClickListener() {
StringBuilder stringBuilder;
@Override
public void onClick(View v) {
//readTextFile(this, R.raw.books);
stringBuilder = new StringBuilder();
String line;
try {
FileInputStream fIn = new FileInputStream(file);
BufferedReader bufferedreader = new BufferedReader(new
InputStreamReader(fIn));
while ((line = bufferedreader.readLine()) != null) {
stringBuilder.append(line);
stringBuilder.append(" ");
stringBuilder.length();
}
bufferedreader.close();
} catch (FileNotFoundException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
String a;
a = String.valueOf(stringBuilder);
String dataArray[];
int t;
dataArray = a.split(" ");
int MP = 0;
for (t = 1; t < dataArray.length - 1; t++) {
float y_0 = Float.valueOf(dataArray[t]);
float y_1 = Float.valueOf(dataArray[t + 1]);
float y_2 = Float.valueOf(dataArray[t - 1]);
float left = y_0 - y_2;
float right = y_1 - y_0;
if (left > 0 && right < 0) {
if (y_0 > MP) {
MP = (int) y_0;
} else {
MP = (int) y_0;
}
Toast.makeText(getApplicationContext(), "Number of peaks
founds\n: " + MP, Toast.LENGTH_SHORT).show();
}
}
DataAlert alert = new DataAlert();
alert.show(getFragmentManager(), "DataAlert");
}
});
//读取数据。
调用=(按钮)findViewById(R.id.Recall);
Recall.setOnClickListener(新视图.OnClickListener(){
StringBuilder StringBuilder;
@凌驾
公共void onClick(视图v){
//readTextFile(this,R.raw.books);
stringBuilder=新的stringBuilder();
弦线;
试一试{
FileInputStream fIn=新的FileInputStream(文件);
BufferedReader BufferedReader=新的BufferedReader(新的
输入流阅读器(fIn);
而((line=bufferedreader.readLine())!=null){
stringBuilder.append(行);
stringBuilder.append(“”);
stringBuilder.length();
}
bufferedreader.close();
}catch(filenotfounde异常){
e、 printStackTrace();
}捕获(IOE异常){
e、 printStackTrace();
}
字符串a;
a=字符串.valueOf(stringBuilder);
字符串数据数组[];
int t;
dataArray=a.split(“”);
int-MP=0;
对于(t=1;t0和右<0){
如果(y_0>MP){
MP=(int)y_0;
}否则{
MP=(int)y_0;
}
Toast.makeText(getApplicationContext(),“峰值数
founds\n:“+MP,Toast.LENGTH\u SHORT.show();
}
}
DataAlert alert=新的DataAlert();
显示(getFragmentManager(),“DataAlert”);
}
});
您对if(y\u 0>MP)行的怀疑是正确的。如果您想制作一个祝酒词,显示找到的峰值数量,那么您需要保留一个峰值列表,或者一个计数器,并在每次发现峰值时将其添加到列表中。然后,在for循环完成对峰的搜索之后,您可以举杯庆祝,说出找到了多少个峰
List<Integer> peaks = new ArrayList<>();
for (t = 1; t < dataArray.length - 1; t++) {
float y_0 = Float.valueOf(dataArray[t]);
float y_1 = Float.valueOf(dataArray[t + 1]);
float y_2 = Float.valueOf(dataArray[t - 1]);
float left = y_0 - y_2;
float right = y_1 - y_0;
if (left > 0 && right < 0)
peaks.add(t);
}
Toast.makeText(getApplicationContext(), "Number of peaks founds\n: " + peaks.size(), Toast.LENGTH_SHORT).show();
for (Integer peak : peaks) {
float value = Float.valueOf(dataArray[peak]);
Toast.makeText(getApplicationContext(), "Peak of height " + value + " found at index " + peak, Toast.LENGTH_SHORT).show();
}
相当于:
MP = (int) y_0;
无论if语句是真是假,您都可以分配
MP=(int)y_0
。我明天早上会回答这个问题。我现在正在打电话,所以编写和格式化代码示例有点尴尬。你好,安德鲁。你能在这方面帮助我吗。
MP = (int) y_0;