Android 活动在使用alertDialog时泄漏了window DecorView

每次我尝试向用户显示警报对话框时，用户都会使用警报内的按钮取消该对话框。我得到以下错误

E/WindowManager: android.view.WindowLeaked: Activity SplashActivity has leaked window DecorView@5f814ed[SplashActivity] that was originally added here
    at android.view.ViewRootImpl.<init>(ViewRootImpl.java:765)
    at android.view.WindowManagerGlobal.addView(WindowManagerGlobal.java:440)
    at android.view.WindowManagerImpl.addView(WindowManagerImpl.java:95)
    at android.app.Dialog.show(Dialog.java:473)
    at SplashActivity.errorDialogue(SplashActivity.java:363)
    at SplashActivity$2.run(SplashActivity.java:196)
    at android.os.Handler.handleCallback(Handler.java:883)
    at android.os.Handler.dispatchMessage(Handler.java:100)
    at android.os.Looper.loop(Looper.java:237)
    at android.app.ActivityThread.main(ActivityThread.java:8016)
    at java.lang.reflect.Method.invoke(Native Method)
    at com.android.internal.os.RuntimeInit$MethodAndArgsCaller.run(RuntimeInit.java:493)
    at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:1076)

然后在onResponseLoaded函数中，我使用runnable函数显示对话框，如下所示：

runOnUiThread(new Runnable() {
                @Override
                public void run() {

                    errorDialogue("Incorrect validation. Please try again"); <-- error here
                }
            });

public void errorDialogue(String message) {

    AlertDialog.Builder dialogBuilder = new AlertDialog.Builder(this);

    LayoutInflater inflater = this.getLayoutInflater();
    View dialogView = inflater.inflate(R.layout.alert_failed_pos_login, null);
    dialogBuilder.setView(dialogView);
    TextView descriptionTextView = (TextView) dialogView.findViewById(R.id.failedMsg);
    descriptionTextView.setText(message);
    //Do your UI operations like dialog opening or Toast here
    errorApiAlertDialog = dialogBuilder.create();
    errorApiAlertDialog.show();  <-- error here

    final Button retryBtn = (Button) dialogView.findViewById(R.id.btntryAgain);
    retryBtn.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {
            errorApiAlertDialog.dismiss();
            finish();
        }
    });
}

---

但我的应用程序并没有崩溃。应用程序显示警报对话框，当我按下重试按钮时，应用程序关闭，并显示上述错误。尝试了许多其他可能的方法来解决这个问题。“活动”泄漏了窗口，我在这里做错了什么？

在从onCreate（）中删除以下重复代码后修复了错误

---

由于onResume和onCreate中的代码都是相同的，所以我发现活动泄露了windows。现在，在从onCreate中删除代码之后，一切都很好

谢谢，投了赞成票。是的，你可以检查自己的答案是否正确，这被认为是s.O.的最佳实践。

runOnUiThread(new Runnable() {
                @Override
                public void run() {

                    errorDialogue("Incorrect validation. Please try again"); <-- error here
                }
            });

public void errorDialogue(String message) {

    AlertDialog.Builder dialogBuilder = new AlertDialog.Builder(this);

    LayoutInflater inflater = this.getLayoutInflater();
    View dialogView = inflater.inflate(R.layout.alert_failed_pos_login, null);
    dialogBuilder.setView(dialogView);
    TextView descriptionTextView = (TextView) dialogView.findViewById(R.id.failedMsg);
    descriptionTextView.setText(message);
    //Do your UI operations like dialog opening or Toast here
    errorApiAlertDialog = dialogBuilder.create();
    errorApiAlertDialog.show();  <-- error here

    final Button retryBtn = (Button) dialogView.findViewById(R.id.btntryAgain);
    retryBtn.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {
            errorApiAlertDialog.dismiss();
            finish();
        }
    });
}

    @Override
protected void onPause() {
    super.onPause();
    if (errorApiAlertDialog != null && errorApiAlertDialog.isShowing()) {
        errorApiAlertDialog.dismiss();
    }
}

@Override
protected void onStop() {
    super.onStop();
    if (errorApiAlertDialog != null && errorApiAlertDialog.isShowing()) {
        errorApiAlertDialog.dismiss();
    }
}

if (getIntent().getStringExtra(getString(R.string.POS_CODE)) != null) {
    RestApi restApi = new RestApi(this, context);
.......//rest code

}