Android 如何呼叫意图颤振打开电话信息菜单?

Android 如何呼叫意图颤振打开电话信息菜单?,android,flutter,dart,Android,Flutter,Dart,onTap在flatter中,我想呼叫mobilecom.android.settings.RadioInfo 我用的是颤振 lteonly() async { final AndroidIntent intent = AndroidIntent( action: 'android.intent.action.MAIN', data: 'com.android.settings.RadioInfo', componentName: null ); aw

onTap
在flatter中,我想呼叫mobile
com.android.settings.RadioInfo

我用的是颤振

lteonly() async {
  final AndroidIntent intent =  AndroidIntent(
   action: 'android.intent.action.MAIN',
   data: 'com.android.settings.RadioInfo',
   componentName: null      
  );
  await intent.launch();  
} 
试试这个:

 AndroidIntent intent = AndroidIntent(
 action: "android.settings.APPLICATION_DETAILS_SETTINGS",
 package: "your_app_package_name",
 data: "package:your_app_package_name",
  );
 intent.launch();

通过kotlin或java在Flatter中添加intent方法