Android 如何呼叫意图颤振打开电话信息菜单?
Android 如何呼叫意图颤振打开电话信息菜单?,android,flutter,dart,Android,Flutter,Dart,onTap在flatter中,我想呼叫mobilecom.android.settings.RadioInfo 我用的是颤振 lteonly() async { final AndroidIntent intent = AndroidIntent( action: 'android.intent.action.MAIN', data: 'com.android.settings.RadioInfo', componentName: null ); aw
onTap
在flatter中,我想呼叫mobilecom.android.settings.RadioInfo
我用的是颤振
lteonly() async {
final AndroidIntent intent = AndroidIntent(
action: 'android.intent.action.MAIN',
data: 'com.android.settings.RadioInfo',
componentName: null
);
await intent.launch();
}
试试这个:
AndroidIntent intent = AndroidIntent(
action: "android.settings.APPLICATION_DETAILS_SETTINGS",
package: "your_app_package_name",
data: "package:your_app_package_name",
);
intent.launch();
通过kotlin或java在Flatter中添加intent方法