android Lrucache:无法检索缓存的位图
我能够将位图插入android Lrucache:无法检索缓存的位图,android,bitmap,out-of-memory,android-lru-cache,Android,Bitmap,Out Of Memory,Android Lru Cache,我能够将位图插入LruCache,但无法检索以前解码的图像。我的数据库中有100多个图像。当我对它进行除臭时,我的gc内存在增加。所以我实现了这个功能以重用解码后的图像 protected void onCreate() { LruCache<String, Bitmap> mMemoryCache; codeforLru_oncreate(); aa1=getBitmapFromMemCache(String.valueOf(aa)); if (aa
LruCache
,但无法检索以前解码的图像。我的数据库中有100多个图像。当我对它进行除臭时,我的gc内存在增加。所以我实现了这个功能以重用解码后的图像
protected void onCreate()
{
LruCache<String, Bitmap> mMemoryCache;
codeforLru_oncreate();
aa1=getBitmapFromMemCache(String.valueOf(aa));
if (aa1 != null)
{
iv.setImageBitmap(aa1);
}
else
{
aa1= decodeSampledBitmapFromResource(aa);
addBitmapToMemoryCache(String.valueOf(aa), aa1);
iv.setImageBitmap(aa1);
}
}
你怎么知道它没有返回解码的图像?你使用1/64最大内存的任何原因?检查@kenWolf:的完整示例,因为我在清单文件中使用了android:largeheap=“true”来增加我的堆。它现在变成了256 mb。因此256/64=4 mb的lrucache。@Amulya Khare:在oncreate中,我正在用toast检查,如果(aa1!=null)它永远不会被输入{iv.setImageBitmap(aa1);}
public void codeforLru_oncreate() {
final int maxMemory = (int) (Runtime.getRuntime().maxMemory() / 1024);
// Use 1/8th of the available memory for this memory cache.
final int cacheSize = maxMemory / 64;
mMemoryCache = new LruCache<String, Bitmap>(cacheSize) {
@Override
protected int sizeOf(String key, Bitmap bitmap) {
// The cache size will be measured in kilobytes rather than
// number of items.
//app.setFlagForMemoryAlloc(1);
return bitmap.getByteCount() / 1024;
}
};
}
// code for adding bitmap into cache memory
public void addBitmapToMemoryCache(String key, Bitmap bitmap)
{
if (getBitmapFromMemCache(key) == null) {
mMemoryCache.put(key, bitmap);
}
}
//code for get bitmap from cache memory
public Bitmap getBitmapFromMemCache(String key) {
return mMemoryCache.get(key);
}
//decoding here......
public Bitmap decodeSampledBitmapFromResource(byte[] decodethis)
{
return BitmapFactory.decodeByteArray(decodethis,0,decodethis.length,option);
}