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Android 异步HTTP请求和Arduino_Android_Arduino_Wifi_Arduino Uno - Fatal编程技术网

Android 异步HTTP请求和Arduino

Android 异步HTTP请求和Arduino,android,arduino,wifi,arduino-uno,Android,Arduino,Wifi,Arduino Uno,我正在开发一个Android应用程序,它将通过Wifi与Arduino Uno进行通信。arduino已经编程为在我访问地址192.168.11.110时打开数字端口号12。当我打开浏览器访问地址时,红色LED(连接到端口12)亮起,当我再次访问时,它熄灭,工作正常。问题是在Android应用程序中,我发出HTTP请求,LED亮起,连接似乎“阻塞”,我无法关闭LED,除非重新启动Arduino或结束Android活动,否则无法通过浏览器访问 我在Android应用程序中用于发出HTTP请求的代码

我正在开发一个Android应用程序,它将通过Wifi与Arduino Uno进行通信。arduino已经编程为在我访问地址192.168.11.110时打开数字端口号12。当我打开浏览器访问地址时,红色LED(连接到端口12)亮起,当我再次访问时,它熄灭,工作正常。问题是在Android应用程序中,我发出HTTP请求,LED亮起,连接似乎“阻塞”,我无法关闭LED,除非重新启动Arduino或结束Android活动,否则无法通过浏览器访问

我在Android应用程序中用于发出HTTP请求的代码如下:

public class ArduinoRequest extends AsyncTask<String, String, String> {

@Override
protected String doInBackground(String... uri) {
    HttpClient httpclient = new DefaultHttpClient();
    HttpResponse response;
    String responseString = null;
    try {
        response = httpclient.execute(new HttpGet(uri[0]));
        StatusLine statusLine = response.getStatusLine();
        if(statusLine.getStatusCode() == HttpStatus.SC_OK){
            ByteArrayOutputStream out = new ByteArrayOutputStream();
            response.getEntity().writeTo(out);
            responseString = out.toString();
            out.close();
        } else{
            //Closes the connection.
            response.getEntity().getContent().close();
            throw new IOException(statusLine.getReasonPhrase());
        }
    } catch (ClientProtocolException e) {
        //TODO Handle problems..
    } catch (IOException e) {
        //TODO Handle problems..
    }
    return responseString;
}

@Override
protected void onPostExecute(String result) {
    super.onPostExecute(result);
    }
}
有什么想法吗?:)

编辑:

我刚刚解决了。请改用此代码:

   // Instantiate the RequestQueue.
              RequestQueue queue = Volley.newRequestQueue(MenuActivity.this);
              String url ="http://192.168.11.110/";

            // Request a string response from the provided URL.
              StringRequest stringRequest = new StringRequest(Request.Method.GET, url,
                      new Response.Listener<String>() {
                          @Override
                          public void onResponse(String response) {
                              // Display the first 500 characters of the response string.
                             // mTextView.setText("Response is: "+ response.substring(0,500));
                          }
                      }, new Response.ErrorListener() {
                  @Override
                  public void onErrorResponse(VolleyError volleyError) {

                  }

              });
//实例化RequestQueue。
RequestQueue=Volley.newRequestQueue(MenuActivity.this);
字符串url=”http://192.168.11.110/";
//从提供的URL请求字符串响应。
StringRequest StringRequest=新的StringRequest(Request.Method.GET,url,
新的Response.Listener(){
@凌驾
公共void onResponse(字符串响应){
//显示响应字符串的前500个字符。
//mTextView.setText(“响应为:”+Response.substring(0500));
}
},new Response.ErrorListener(){
@凌驾
公共错误响应(截击错误截击错误){
}
});

您的问题解决了吗?是的,我编辑了帖子并发布了解决方案
   // Instantiate the RequestQueue.
              RequestQueue queue = Volley.newRequestQueue(MenuActivity.this);
              String url ="http://192.168.11.110/";

            // Request a string response from the provided URL.
              StringRequest stringRequest = new StringRequest(Request.Method.GET, url,
                      new Response.Listener<String>() {
                          @Override
                          public void onResponse(String response) {
                              // Display the first 500 characters of the response string.
                             // mTextView.setText("Response is: "+ response.substring(0,500));
                          }
                      }, new Response.ErrorListener() {
                  @Override
                  public void onErrorResponse(VolleyError volleyError) {

                  }

              });