Android 异步HTTP请求和Arduino
我正在开发一个Android应用程序,它将通过Wifi与Arduino Uno进行通信。arduino已经编程为在我访问地址192.168.11.110时打开数字端口号12。当我打开浏览器访问地址时,红色LED(连接到端口12)亮起,当我再次访问时,它熄灭,工作正常。问题是在Android应用程序中,我发出HTTP请求,LED亮起,连接似乎“阻塞”,我无法关闭LED,除非重新启动Arduino或结束Android活动,否则无法通过浏览器访问 我在Android应用程序中用于发出HTTP请求的代码如下:Android 异步HTTP请求和Arduino,android,arduino,wifi,arduino-uno,Android,Arduino,Wifi,Arduino Uno,我正在开发一个Android应用程序,它将通过Wifi与Arduino Uno进行通信。arduino已经编程为在我访问地址192.168.11.110时打开数字端口号12。当我打开浏览器访问地址时,红色LED(连接到端口12)亮起,当我再次访问时,它熄灭,工作正常。问题是在Android应用程序中,我发出HTTP请求,LED亮起,连接似乎“阻塞”,我无法关闭LED,除非重新启动Arduino或结束Android活动,否则无法通过浏览器访问 我在Android应用程序中用于发出HTTP请求的代码
public class ArduinoRequest extends AsyncTask<String, String, String> {
@Override
protected String doInBackground(String... uri) {
HttpClient httpclient = new DefaultHttpClient();
HttpResponse response;
String responseString = null;
try {
response = httpclient.execute(new HttpGet(uri[0]));
StatusLine statusLine = response.getStatusLine();
if(statusLine.getStatusCode() == HttpStatus.SC_OK){
ByteArrayOutputStream out = new ByteArrayOutputStream();
response.getEntity().writeTo(out);
responseString = out.toString();
out.close();
} else{
//Closes the connection.
response.getEntity().getContent().close();
throw new IOException(statusLine.getReasonPhrase());
}
} catch (ClientProtocolException e) {
//TODO Handle problems..
} catch (IOException e) {
//TODO Handle problems..
}
return responseString;
}
@Override
protected void onPostExecute(String result) {
super.onPostExecute(result);
}
}
有什么想法吗?:)
编辑:
我刚刚解决了。请改用此代码:
// Instantiate the RequestQueue.
RequestQueue queue = Volley.newRequestQueue(MenuActivity.this);
String url ="http://192.168.11.110/";
// Request a string response from the provided URL.
StringRequest stringRequest = new StringRequest(Request.Method.GET, url,
new Response.Listener<String>() {
@Override
public void onResponse(String response) {
// Display the first 500 characters of the response string.
// mTextView.setText("Response is: "+ response.substring(0,500));
}
}, new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError volleyError) {
}
});
//实例化RequestQueue。
RequestQueue=Volley.newRequestQueue(MenuActivity.this);
字符串url=”http://192.168.11.110/";
//从提供的URL请求字符串响应。
StringRequest StringRequest=新的StringRequest(Request.Method.GET,url,
新的Response.Listener(){
@凌驾
公共void onResponse(字符串响应){
//显示响应字符串的前500个字符。
//mTextView.setText(“响应为:”+Response.substring(0500));
}
},new Response.ErrorListener(){
@凌驾
公共错误响应(截击错误截击错误){
}
});
您的问题解决了吗?是的,我编辑了帖子并发布了解决方案
// Instantiate the RequestQueue.
RequestQueue queue = Volley.newRequestQueue(MenuActivity.this);
String url ="http://192.168.11.110/";
// Request a string response from the provided URL.
StringRequest stringRequest = new StringRequest(Request.Method.GET, url,
new Response.Listener<String>() {
@Override
public void onResponse(String response) {
// Display the first 500 characters of the response string.
// mTextView.setText("Response is: "+ response.substring(0,500));
}
}, new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError volleyError) {
}
});