如何在AngularJS中旋转base64图像
我有一个包含base64图像的json源代码,我希望以纵向方式显示它们。我想我需要构建一个图像对象数组,并在构建数组时旋转它们,但我不确定如何在视图中显示图像对象 这就是我构建的阵列如何在AngularJS中旋转base64图像,angularjs,Angularjs,我有一个包含base64图像的json源代码,我希望以纵向方式显示它们。我想我需要构建一个图像对象数组,并在构建数组时旋转它们,但我不确定如何在视图中显示图像对象 这就是我构建的阵列 angular.forEach($scope.trayDetails.tray_images, function(trayImage) { var myBase64 = "data:image/png;base64,"+trayImage.data; var img = new Image();
angular.forEach($scope.trayDetails.tray_images, function(trayImage) {
var myBase64 = "data:image/png;base64,"+trayImage.data;
var img = new Image();
img.src = myBase64;
if (img.width>img.height ) {
$(img).css({
'transform': "rotate(90deg)"
});
}
$scope.savedPictures.push(img);
});
但现在我不确定该如何处理数组,我尝试了这两种方法,但都没有成功
<li ng-repeat="savedPicture in savedPictures" class="photo">
{{savedPicture}}
</li>
<li ng-repeat="savedPicture in savedPictures" class="photo">
<img ng-src="{{savedPicture}}" />
</li>
{{savedPicture}
解决方案比您想象的要简单:
angular.forEach($scope.trayDetails.tray_images, function(trayImage) {
var myBase64 = "data:image/png;base64,"+trayImage.data;
var img = new Image();
img.src = myBase64;
img.isRotated = img.width > img.height; //Use css class to rotate
$scope.savedPictures.push(img);
});
然后将img添加到html中:
<li ng-repeat="savedPicture in savedPictures" class="photo">
<img ng-class="{rotateImg: savedPicture.isRotated}" ng-src="{{savedPicture.src}}" />
</li>
.rotateImg : { transform: rotate(90deg); }