Asp.net 需要字符串中的第二个单词。如何做？

我有一个字符串变量，其中包含“Welcom Salatia”

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我想把salathia储存到另一个字符串。。。。如何使用vb.net在asp.net中执行此操作您可以使用split并获取第二个字符串

Dim s As String = "Welcom salathia"
' Split string based on spaces
Dim words As String() = s.Split(New Char() {" "c})

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您可以使用split并获取第二个字符串

Dim s As String = "Welcom salathia"
' Split string based on spaces
Dim words As String() = s.Split(New Char() {" "c})

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可以使用contains函数获取第一个空格及其索引，然后获取字符，直到找到下一个空格

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拆分函数在这方面也很有用。这也会更简单。

您可以使用contains函数获取第一个空格及其索引，然后获取字符，直到找到下一个空格

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拆分函数在这方面也很有用。而且这也是一种更简单的方法。

方法1:

Dim s As String = "Welcom salathia"
s = s.Split(" ".ToCharArray)(1)

Dim s As String = "Welcom salathia"
s = s.substring(s.index(" ")) 

方式2:

Dim s As String = "Welcom salathia"
s = s.Split(" ".ToCharArray)(1)

Dim s As String = "Welcom salathia"
s = s.substring(s.index(" ")) 

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方式1:

Dim s As String = "Welcom salathia"
s = s.Split(" ".ToCharArray)(1)

Dim s As String = "Welcom salathia"
s = s.substring(s.index(" ")) 

方式2:

Dim s As String = "Welcom salathia"
s = s.Split(" ".ToCharArray)(1)

Dim s As String = "Welcom salathia"
s = s.substring(s.index(" ")) 

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以防有空间运行

    Dim s As String = "Welcom   salathia"
    ' Split string based on spaces, gurad against runs of space
    Dim words() As String = s.Split(New Char() {" "c}, StringSplitOptions.RemoveEmptyEntries)
    Debug.WriteLine(words(1)) 'show second word

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以防有空间运行

    Dim s As String = "Welcom   salathia"
    ' Split string based on spaces, gurad against runs of space
    Dim words() As String = s.Split(New Char() {" "c}, StringSplitOptions.RemoveEmptyEntries)
    Debug.WriteLine(words(1)) 'show second word

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什么构成一个单词？任何不包含空格的东西都是一个单词吗？你试过我的答案了吗。？我有一个疑问。！该变量是否只包含字符串“Welcom salathia”或它也包含其他字符串。？构成单词的是什么？任何不包含空格的内容都是单词吗？您是否尝试过我的答案。？我有一个疑问。！该变量是否只包含字符串“Welcom salathia”或它也包含其他字符串。？Dim txt_addedbyuser As string=Welcome_id.Text Dim string_split As string=txt_addedbyuser.split（New Char（）{”“c}）在vb.net中显示错误“字符串的1-D类型数组值无法转换为字符串”。您还可以编写：Dim WORKS As string（）=Split（s，“”）Dim txt_addedbyuser As String=Welcome_id.Text Dim String_Split As String=txt_addedbyuser.Split（New Char（）{“c}）在vb.net中显示错误“字符串的1-D数组的值无法转换为字符串”。您还可以编写：Dim words As String（）=Split（s，“”）