仅使用awk和sed修改第2列

我有一个包含3列的列表：

2547123456789,5391074043372870,639027123456789

我想修改第二列，如下所示：

sed 's/\([0-9]\)\([0-9]\)/\2\1/g' so that it becomes:

3519700434738207

我的问题是如何在awk/sed的一行中执行此操作，同时保持其他列不变，以便最终文件具有：

2547123456789,3519700434738207,639027123456789

谢谢

输出

awk-F，'{printf（“%s，”，$1）；len=split（$2，a，”）；for（i=1；i试试这个：

sed 'h;s/.*,\([^,]*\),.*/\1/;s/\(.\)\(.\)/\2\1/g;G;s/\([^\n]*\)\n\([^,]*,\)[^,]*\(.*\)/\2\1\3/' inputfile

说明：

# copy the line to hold space
h;
# capture the second column and retain it in pattern space
s/.*,\([^,]*\),.*/\1/;
# swap each pair of characters
s/\(.\)\(.\)/\2\1/g;
# append the contents of hold space, now pattern space looks like
# new_field_2[newline]field_1,old_field_2,field_3
G;
# capture the fields that we want and arrange them in the proper order
s/\([^\n]*\)\n\([^,]*,\)[^,]*\(.*\)/\2\1\3/

您接受的答案与您要求的结果不一致。它只翻转了第二个字段的前2个字符。如果这是您真正想要的，请更新您的问题以反映这一点。谢谢我误读了问题，认为
g
标志将拾取第二列。如果OP能够确认他想要的内容，我将elete我的回答…+1，有一刻我觉得用sed一行是不可能的；）工作得很有魅力：-）谢谢
awk -F, '{printf("%s,",$1);len=split($2,a,"");for(i=1;i<len;i+=2)printf("%s%s",a[i+1],a[i]);printf(",%s\n",$3)}' ./infile
2547123456789,3519700434738207,639027123456789
1234567890123,2143658709214365,123456789012345

sed 'h;s/.*,\([^,]*\),.*/\1/;s/\(.\)\(.\)/\2\1/g;G;s/\([^\n]*\)\n\([^,]*,\)[^,]*\(.*\)/\2\1\3/' inputfile

# copy the line to hold space
h;
# capture the second column and retain it in pattern space
s/.*,\([^,]*\),.*/\1/;
# swap each pair of characters
s/\(.\)\(.\)/\2\1/g;
# append the contents of hold space, now pattern space looks like
# new_field_2[newline]field_1,old_field_2,field_3
G;
# capture the fields that we want and arrange them in the proper order
s/\([^\n]*\)\n\([^,]*,\)[^,]*\(.*\)/\2\1\3/