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基于匹配正则表达式的Awk脚本值提取

awk grep

基于匹配正则表达式的Awk脚本值提取,awk,grep,Awk,Grep,我正在尝试编写一个awk脚本，在其中捕获一个API响应。响应如下所示 id:0tesss status:ACTIVE created:2016-12-06T13:24:50.000Z activated:2016-12-06T13:26:06.000Z statusChanged:2016-12-06T13:26:06.000Z lastLogin:2017-06-13T06:32:41.000Z lastUpdated:2017-06-13T06:32:58.000Z passwordChan

我正在尝试编写一个
awk
脚本，在其中捕获一个API响应。响应如下所示

id:0tesss status:ACTIVE created:2016-12-06T13:24:50.000Z activated:2016-12-06T13:26:06.000Z statusChanged:2016-12-06T13:26:06.000Z lastLogin:2017-06-13T06:32:41.000Z lastUpdated:2017-06-13T06:32:58.000Z passwordChanged:null profile:lastName:tack profile:secondEmail:null profile:mobilePhone:null profile:email:karry.t@john.com profile:login:karry.t@john.com profile:firstName:Karry profile:displayName:Karry tack credentials:recovery_question:{question:Who's a ?}
在上面，我只想打印下面的
profile:login
值

karry.t@john.com
我怎样才能打印这个。对于不同的用户，此响应可能有所不同。因此，我必须根据
profile.login
进行过滤，并将其打印到csv文件旁边。感谢您的帮助。

您可以使用此命令（使用
tr
和
awk
）：

样本：

AMD$ echo "id:0tesss status:ACTIVE created:2016-12-06T13:24:50.000Z activated:2016-12-06T13:26:06.000Z statusChanged:2016-12-06T13:26:06.000Z lastLogin:2017-06-13T06:32:41.000Z lastUpdated:2017-06-13T06:32:58.000Z passwordChanged:null profile:lastName:tack profile:secondEmail:null profile:mobilePhone:null profile:email:karry.t@john.com profile:login:karry.t@john.com profile:firstName:Karry profile:displayName:Karry tack credentials:recovery_question:{question:Who's a ?}" | tr ' ' '\n' | awk -F: '/profile:login/{print $NF}'
karry.t@john.com

AMD$ echo "id:0tesss status:ACTIVE created:2016-12-06T13:24:50.000Z activated:2016-12-06T13:26:06.000Z statusChanged:2016-12-06T13:26:06.000Z lastLogin:2017-06-13T06:32:41.000Z lastUpdated:2017-06-13T06:32:58.000Z passwordChanged:null profile:lastName:tack profile:secondEmail:null profile:mobilePhone:null profile:email:karry.t@john.com profile:login:karry.t@john.com profile:firstName:Karry profile:displayName:Karry tack credentials:recovery_question:{question:Who's a ?}" | awk -vRS=' ' '/profile:login/{sub(/.*:/, ""); print}'
karry.t@john.com
或者只使用
awk
：

tr ' ' '\n' | awk -F: '/profile:login/{print $NF}'

awk -vRS=' ' '/profile:login/{sub(/.*:/, ""); print}'
样本：

AMD$ echo "id:0tesss status:ACTIVE created:2016-12-06T13:24:50.000Z activated:2016-12-06T13:26:06.000Z statusChanged:2016-12-06T13:26:06.000Z lastLogin:2017-06-13T06:32:41.000Z lastUpdated:2017-06-13T06:32:58.000Z passwordChanged:null profile:lastName:tack profile:secondEmail:null profile:mobilePhone:null profile:email:karry.t@john.com profile:login:karry.t@john.com profile:firstName:Karry profile:displayName:Karry tack credentials:recovery_question:{question:Who's a ?}" | tr ' ' '\n' | awk -F: '/profile:login/{print $NF}'
karry.t@john.com

AMD$ echo "id:0tesss status:ACTIVE created:2016-12-06T13:24:50.000Z activated:2016-12-06T13:26:06.000Z statusChanged:2016-12-06T13:26:06.000Z lastLogin:2017-06-13T06:32:41.000Z lastUpdated:2017-06-13T06:32:58.000Z passwordChanged:null profile:lastName:tack profile:secondEmail:null profile:mobilePhone:null profile:email:karry.t@john.com profile:login:karry.t@john.com profile:firstName:Karry profile:displayName:Karry tack credentials:recovery_question:{question:Who's a ?}" | awk -vRS=' ' '/profile:login/{sub(/.*:/, ""); print}'
karry.t@john.com
您可以使用此命令执行此操作（使用
tr
和
awk
）：

样本：

AMD$ echo "id:0tesss status:ACTIVE created:2016-12-06T13:24:50.000Z activated:2016-12-06T13:26:06.000Z statusChanged:2016-12-06T13:26:06.000Z lastLogin:2017-06-13T06:32:41.000Z lastUpdated:2017-06-13T06:32:58.000Z passwordChanged:null profile:lastName:tack profile:secondEmail:null profile:mobilePhone:null profile:email:karry.t@john.com profile:login:karry.t@john.com profile:firstName:Karry profile:displayName:Karry tack credentials:recovery_question:{question:Who's a ?}" | tr ' ' '\n' | awk -F: '/profile:login/{print $NF}'
karry.t@john.com

AMD$ echo "id:0tesss status:ACTIVE created:2016-12-06T13:24:50.000Z activated:2016-12-06T13:26:06.000Z statusChanged:2016-12-06T13:26:06.000Z lastLogin:2017-06-13T06:32:41.000Z lastUpdated:2017-06-13T06:32:58.000Z passwordChanged:null profile:lastName:tack profile:secondEmail:null profile:mobilePhone:null profile:email:karry.t@john.com profile:login:karry.t@john.com profile:firstName:Karry profile:displayName:Karry tack credentials:recovery_question:{question:Who's a ?}" | awk -vRS=' ' '/profile:login/{sub(/.*:/, ""); print}'
karry.t@john.com
或者只使用
awk
：

tr ' ' '\n' | awk -F: '/profile:login/{print $NF}'

awk -vRS=' ' '/profile:login/{sub(/.*:/, ""); print}'
样本：

AMD$ echo "id:0tesss status:ACTIVE created:2016-12-06T13:24:50.000Z activated:2016-12-06T13:26:06.000Z statusChanged:2016-12-06T13:26:06.000Z lastLogin:2017-06-13T06:32:41.000Z lastUpdated:2017-06-13T06:32:58.000Z passwordChanged:null profile:lastName:tack profile:secondEmail:null profile:mobilePhone:null profile:email:karry.t@john.com profile:login:karry.t@john.com profile:firstName:Karry profile:displayName:Karry tack credentials:recovery_question:{question:Who's a ?}" | tr ' ' '\n' | awk -F: '/profile:login/{print $NF}'
karry.t@john.com

AMD$ echo "id:0tesss status:ACTIVE created:2016-12-06T13:24:50.000Z activated:2016-12-06T13:26:06.000Z statusChanged:2016-12-06T13:26:06.000Z lastLogin:2017-06-13T06:32:41.000Z lastUpdated:2017-06-13T06:32:58.000Z passwordChanged:null profile:lastName:tack profile:secondEmail:null profile:mobilePhone:null profile:email:karry.t@john.com profile:login:karry.t@john.com profile:firstName:Karry profile:displayName:Karry tack credentials:recovery_question:{question:Who's a ?}" | awk -vRS=' ' '/profile:login/{sub(/.*:/, ""); print}'
karry.t@john.com

awk
可以提取文件中所需的内容

$ awk '{match($0,/profile:login[^\ ]+/);print substr($0,RSTART+14,RLENGTH-14)}' file
karry.t@john.com
简要说明

  • match（$0，/profile:login[^\]+/）
    ：在
    $0
    中找到与正则表达式匹配的模式，并将起点存储在
    RSTART
    中，长度以
    RLENGTH
  • substr（$0，RSTART+14，RLENGTH-14）}
    ：打印忽略先前不需要的模式的子字符串
      • awk
      可以从文件中提取所需内容

      $ awk '{match($0,/profile:login[^\ ]+/);print substr($0,RSTART+14,RLENGTH-14)}' file
karry.t@john.com
      简要说明

      • match（$0，/profile:login[^\]+/）
        ：在
        $0
        中找到与正则表达式匹配的模式，并将起点存储在
        RSTART
        中，长度以
        RLENGTH
      • substr（$0，RSTART+14，RLENGTH-14）}
        ：打印忽略先前不需要的模式的子字符串
      哎呀，你忘记发布代码了！StackOverflow是关于帮助人们修复代码的。这不是免费的编码服务。有代码总比没有代码好。即使你不知道如何编写程序，元代码也会证明你认为程序应该如何工作。哎呀，你忘了发布代码了！StackOverflow是关于帮助人们修复代码的。这不是免费的编码服务。有代码总比没有代码好。即使您不知道如何编写程序，元代码也会演示您认为程序应该如何工作。