Awk 如何编辑Unix文件以在2个特定模式匹配后插入几行

我有一个文件，内容如下。我想编辑该文件，以便在文件中看到LTPGY模式时，在“set t table new$m table]”行之后插入一行内容为“FOUND”的新行

输入文件如下所示：-

  set ra [ 1 22 3 ] LTPGY
  set a 0
  set a1 1

  set t [ table new $m table]
  set a [  $t process_axis]
  set a [  $t voltage_axis]



  set ra [ 1 22 3 ] STPGY
  set a 0
  set a1 1

  set t [ table new $m table]
  set a [  $t process_axis]
  set a [  $t voltage_axis]


  set ra [ 1 22 3 ] LTPGY
  set a 0
  set a1 1

  set t [ table new $m table]
  set a [  $t process_axis]
  set a [  $t voltage_axis]



  set ra [ 1 22 3 ] STPGY
  set a 0
  set a1 1

  set t [ table new $m table]
  set a [  $t process_axis]
  set a [  $t voltage_axis]

我希望输出如下所示：-

  set ra [ 1 22 3 ] LTPGY
  set a 0
  set a1 1

  set t [ table new $m table]
  FOUND
  set a [  $t process_axis]
  set a [  $t voltage_axis]



  set ra [ 1 22 3 ] STPGY
  set a 0
  set a1 1

  set t [ table new $m table]
  set a [  $t process_axis]
  set a [  $t voltage_axis]


  set ra [ 1 22 3 ] LTPGY
  set a 0
  set a1 1

  set t [ table new $m table]
  FOUND
  set a [  $t process_axis]
  set a [  $t voltage_axis]



  set ra [ 1 22 3 ] STPGY
  set a 0
  set a1 1

  set t [ table new $m table]
  set a [  $t process_axis]
  set a [  $t voltage_axis]

---

适用于gawk，未在其他AWK上测试：

gawk '
    /set ra / {found = /LTPGY/}
    1;
    index($0, "set t [ table new $m table]") && found {print "FOUND"}
' file

这可能适用于您（GNU-sed）：

---

将注意力集中在

LTPGY

后面的行上，并找到所需的字符串，将其打印出来，然后用所需的字符串

FOUND

替换除前导空格以外的所有空格。这有点宽泛。您能指出输出文件的确切外观吗？另外，分享你的尝试也很好

sed '/LTPGY/{:a;n;/set t \[ table new $m table\]/!ba;p;s/\S.*/FOUND/}' file