将带有文件夹的文件移动到bash中的新文件夹

假设我们有一堆来自

find development/js-name“*.js”

它返回类似于

development/js/folder1/*.js
development/js/folder2/*.js

我们需要转移到

# as you can see folder 1 & 2 is the same but diffrent folder
production/js/folder1/*.js
production/js/folder2/*.js

我们如何像上面那样在bash中移动文件

谢谢

编辑*这是我要做的

#!/bin/bash
devel_file_js=`find ../../development/js -name "*.js"`
production_folder=`../../production/js`
for i in $devel_file_js; 
do 
    mv #hmm
done

亚当·拉马丹

你是说像“mv”：p

您可以执行以下操作：

#!/bin/bash
dev_folder="../../development/js";
production_folder="../../production/js"

for old_location in $(find $dev_folder -name "*.js") 
do 
    new_location=$(echo ${old_location/${dev_folder}/${production_folder}/})
    new_dirname=$(dirname ${new_location})

    echo "Moving ${old_location} to ${new_location}"

    # Create folder if not exists
    if [[ ! -d ${new_dirname} ]]
    then
        mkdir -p ${new_dirname}
    fi

    # mv ${old_location} ${new_location}
done

---

是的，但是我把逻辑和保留文件夹名搞混了。我想到的是使用regex并搜索development/js，用production/js或类似的东西来更改它。wew这很复杂，${}如何工作？工作很好！但是mkdir仍然有缺陷，当它位于递归文件夹中时无法工作，有一个正确吗？很好，很抱歉缺少-p选项。对于第7行，它用匹配模式的结果替换字符串，如下所示：${/}