Bash 运行ssh远程命令和grep获取字符串

我想编写脚本，远程运行一些ssh远程命令。我所需要的只是将已执行命令的输出grep为某个特殊字符串，这将意味着该命令已成功执行。例如，当我运行此命令时：

ssh user@host "sudo /etc/init.d/haproxy stop"

我得到输出：

Stopping haproxy: [  OK  ]

---

我所需要的就是找到“OK”字符串，以确保命令成功执行。如何执行此操作？

添加

grep

并检查退出状态：

ssh user@host "sudo /etc/init.d/haproxy stop | grep -Fq '[  OK  ]'"
if [ "$#" -eq 0 ]; then
    echo "Command ran successfully."
else
    echo "Command failed."
fi

command && { echo "Command ran successfully."; }
command || { echo "Command failed."; }
if command; then echo "Command ran successfully."; else echo "Command failed."; fi

您也可以将

grep

放置在外部

ssh user@host "sudo /etc/init.d/haproxy stop" | grep -Fq '[  OK  ]'

检查退出状态的其他方法：

ssh user@host "sudo /etc/init.d/haproxy stop | grep -Fq '[  OK  ]'"
if [ "$#" -eq 0 ]; then
    echo "Command ran successfully."
else
    echo "Command failed."
fi

command && { echo "Command ran successfully."; }
command || { echo "Command failed."; }
if command; then echo "Command ran successfully."; else echo "Command failed."; fi

您还可以捕获输出并将其与

案例

或

[[]]

进行比较：

OUTPUT=$(exec ssh user@host "sudo /etc/init.d/haproxy stop")
case "$OUTPUT" in
*'[  OK  ]'*)
    echo "Command ran successfully."
    ;;
*)
    echo "Command failed."
esac

if [[ $OUTPUT == *'[  OK  ]'* ]]; then
    echo "Command ran successfully."
else
    echo "Command failed."
fi

您可以嵌入

$（exec sshuser@host“sudo/etc/init.d/haproxy-stop”）

直接作为表达式，而不是根据需要将输出传递给变量

如果

/etc/init.d/haproxy stop

将消息发送到stderr，只需将其重定向到stdout即可捕获：

sudo /etc/init.d/haproxy stop 2>&1