Bash 文件中的多个附件

早上好，我想通过mutt发送带有文本文件附件列表的电子邮件

这是我的密码：

#!/bin/bash
subj=$(cat /home/lazuardi/00000000042/subject.txt)
attc=$(find /home/lazuardi/00000000042 -name "*.*" | grep -v body.txt | grep -v email.txt | grep -v subject.txt | grep -v body.html > attachment.txt)
ls=$(for x in $attc; do read; done)
while read recp; do
    while read ls; do
        mutt -e "set content_type=text/html" $recp -s "$subj" -- $ls < /home/lazuardi/00000000042
    done < /home/lazuardi/attachment.txt
done < /home/lazuardi/00000000042/email.txt 

#/bin/bash
subc=$（cat/home/lazuardi/00000000042/subject.txt）
attc=$（find/home/lazuardi/00000000042-name“****”| grep-v body.txt | grep-v email.txt | grep-v subject.txt | grep-v body.html>attachment.txt）
ls=$（对于$attc中的x；执行读取；执行完毕）
读recp时；做
读ls时；做
mutt-e“set content_type=text/html”$recp-s“$subj”-$ls

我仍然无法在attachment.txt中附加文件 我尝试了FOR循环，结果是一样的。

---

我该怎么做？

您应该将变量放在引号周围，以防止分词。它会导致单个参数变为两个或多个：

mutt -e "set content_type=text/html" "$recp" -s "$subj" -- "$ls" < /home/lazuardi/00000000042

这里的作业也没有意义：

attc=$(find /home/lazuardi/00000000042 -name "*.*" | grep -v body.txt | grep -v email.txt | grep -v subject.txt | grep -v body.html > attachment.txt)
ls=$(for x in $attc; do read; done)

试试这个：

#!/bin/bash

subj=$(</home/lazuardi/00000000042/subject.txt)

attachments=()
while IFS= read -r file; do
    attachments+=("$file")
done < <(exec find /home/lazuardi/00000000042 -name "*.*" | grep -v -e body.txt -e email.txt -e subject.txt -e body.html)

echo '---- Attachments ----'
printf '%s\n' "${attachments[@]}"
echo

recipients=()
while read recp; do
    recipients+=("$recp")
done < /home/lazuardi/00000000042/email.txt

echo '---- Recipients ----'
printf '%s\n' "${recipients[@]}"
echo

for recp in "${recipients[@]}"; do
    for attachment in "${attachments[@]}"; do
        echo "Sending content to $recp with subject $subj and attachment $attachment."
        mutt -e "set content_type=text/html" "$recp" -s "$subj" -- "$attachment" < /home/lazuardi/00000000042/body.txt
    done
done

#/bin/bash
sub=$（对
attc
的赋值没有任何作用，因为您正在将输出重定向到一个文件。对
ls
的赋值也很奇怪（如果
$attc
实际包含任何内容，则会挂起stdin的输入）。那么我应该如何编写呢？我尝试在没有ls的情况下只使用了1次（而读取recp；do）但是它有相同的结果。
attc
应该包含什么？ls

应该包含什么？为什么要将目录作为标准输入提供给mutt？您是在尝试发送一封电子邮件还是多封电子邮件？您在这个脚本的任何地方都没有使用

-a

参数作为附件。您不应该这样做吗？在attc中我想，我可以使用附件的contain作为变量，用ls变量读取变量。我想发送多封电子邮件，其中包含来自文件的列表收件人、来自文件的主题和来自文件的附件列表。我应该在代码中的哪里更正？是一组平行列表需要合并在每个文件中的一行？还是您需要将所有主题发送到每个附件的所有电子邮件地址？

#!/bin/bash

subj=$(</home/lazuardi/00000000042/subject.txt)

attachments=()
while IFS= read -r file; do
    attachments+=("$file")
done < <(exec find /home/lazuardi/00000000042 -name "*.*" | grep -v -e body.txt -e email.txt -e subject.txt -e body.html)

echo '---- Attachments ----'
printf '%s\n' "${attachments[@]}"
echo

recipients=()
while read recp; do
    recipients+=("$recp")
done < /home/lazuardi/00000000042/email.txt

echo '---- Recipients ----'
printf '%s\n' "${recipients[@]}"
echo

for recp in "${recipients[@]}"; do
    for attachment in "${attachments[@]}"; do
        echo "Sending content to $recp with subject $subj and attachment $attachment."
        mutt -e "set content_type=text/html" "$recp" -s "$subj" -- "$attachment" < /home/lazuardi/00000000042/body.txt
    done
done

#!/bin/bash

subj=$(</home/lazuardi/00000000042/subject.txt)

readarray -t attachments \
    < <(exec find /home/lazuardi/00000000042 -name "*.*" | grep -v -e body.txt -e email.txt -e subject.txt -e body.html)

echo '---- Attachments ----'
printf '%s\n' "${attachments[@]}"
echo

readarray -t recipients < /home/lazuardi/00000000042/email.txt

echo '---- Recipients ----'
printf '%s\n' "${recipients[@]}"
echo

for recp in "${recipients[@]}"; do
    for attachment in "${attachments[@]}"; do
        echo "Sending content to $recp with subject $subj and attachment $attachment."
        mutt -e "set content_type=text/html" "$recp" -s "$subj" -- "$attachment" < /home/lazuardi/00000000042/body.txt
    done
done