Bash 如何预设一段时间'；前'；（从现在开始的相对时间）
如何显示给定日期的时间。例如：Bash 如何预设一段时间'；前'；（从现在开始的相对时间）,bash,command-line,date-formatting,Bash,Command Line,Date Formatting,如何显示给定日期的时间。例如： echo "File was modified `date -r file.txt`" DATE=$(date -r file.txt +%s) NOW=$(date +%s) DIFF=$(expr $NOW - $DATE) SEC=$((DIFF % 60)) DIFF=$((DIFF / 60)) MIN=$((DIFF % 60)) DIFF=$((DIFF / 60)) HOUR=$((DIFF % 24)) DIFF=$((DIFF / 2
echo "File was modified `date -r file.txt`"
DATE=$(date -r file.txt +%s)
NOW=$(date +%s)
DIFF=$(expr $NOW - $DATE)
SEC=$((DIFF % 60))
DIFF=$((DIFF / 60))
MIN=$((DIFF % 60))
DIFF=$((DIFF / 60))
HOUR=$((DIFF % 24))
DIFF=$((DIFF / 24))
DAY=$DIFF
echo $DAY days, $HOUR hours, $MIN mins, $SEC seconds ago.
File was modified Tue Jan 7 00:52:40 GMT 2014
File was modified 3 seconds ago
File was modified 1 hour ago
File was modified 2 days ago
File was modified 3 weeks ago
（这不是只指定整天的副本。）您可以使用“执行一些模运算”来完成此操作。例如：
echo "File was modified `date -r file.txt`"
DATE=$(date -r file.txt +%s)
NOW=$(date +%s)
DIFF=$(expr $NOW - $DATE)
SEC=$((DIFF % 60))
DIFF=$((DIFF / 60))
MIN=$((DIFF % 60))
DIFF=$((DIFF / 60))
HOUR=$((DIFF % 24))
DIFF=$((DIFF / 24))
DAY=$DIFF
echo $DAY days, $HOUR hours, $MIN mins, $SEC seconds ago.
今天我遇到了一个类似的问题，并为此编写了一个函数：
time_ago() {
if (( $# < 1 )); then
local u=$(tput smul) # underline
local n=$(tput rmul) # no underline
echo "usage: time_ago ${u}timestamp_ago${n} [${u}timestamp_now${n}]"
exit 1
fi
local minutes=60
local hours=$(( 60 * minutes ))
local days=$(( 24 * hours ))
local diff=$(( ${2:-$(date +%s)} - $1 ))
local human
if (( diff < 30 )); then
human="${diff} seconds"
elif (( diff < 90 )); then
human="1 minute"
elif (( diff < 1 * hours )); then
human="$(( (diff + minutes / 2) / minutes )) minutes"
elif (( diff < 1 * hours + 30 * minutes )); then
human="about 1 hour"
elif (( diff < 1 * days )); then
human="about $(( (diff + hours / 2) / hours )) hours"
elif (( diff < 2 * days)); then
human="1 day"
else
human="$(( (diff + days / 2) / days)) days"
fi
echo "$human ago"
}
if [[ "$0" = "./time_ago" ]];then
time_ago 1556324045 1556540404 # 3 days ago
time_ago 1556424045 1556540404 # 1 day ago
time_ago 1556534045 1556540404 # about 2 hours ago
time_ago 1556536045 1556540404 # about 1 hour ago
time_ago 1556539145 1556539875 # 12 minutes ago
time_ago 1556539900 1556539921 # 21 seconds ago
time_ago
fi
time\u ago（）{
如果（$#<1））；那么
本地u=$（tput smul）#下划线
本地n=$（tput rmul）#无下划线
echo“用法：time_ago${u}timestamp_ago${n}[${u}timestamp_now${n}]”
出口1
fi
本地分钟=60
当地时间=$（（60*分钟））
当地天数=$（24小时））
本地差异=$（${2:-$（日期+%s）}-$1））
当地人
如果（（差值<30））；则
human=“${diff}秒”
elif（（差值<90））；然后
human=“1分钟”
elif（（差值<1*h））；然后
人力=“$（（差异+分钟/2）/分钟）分钟”
elif（（差值<1*小时+30*分钟））；然后
human=“大约1小时”
elif（（差值<1*天））；然后
human=“大约$（（差异+小时/2）/小时）小时”
elif（（差值<2*天））；然后
人类=“1天”
其他的
人力=“$（（差异+天/2）/天”）天”
fi
echo“$human ago”
}
如果[[“$0”=”/“时间”]；然后
时间1556324045 1556540404三天前
时间1556424045 1556540404一天前
时间是1556534045 1556540404，大约2小时前
时间是1556536045 1556540404，大约1小时前
时间1556539145 1556539875？12分钟前
时间1556539900 1556539921秒前
很久以前
fi
它是可用的，就像您想要评论/编辑一样。时间间隔的灵感来源于。对于日期算术，您最好的选择是更高级的编程语言，如Python。这可以为您提供构建算法的想法。这开始接近我所追求的，但它显示了冗余使用（例如
0天、0小时、0分钟、15秒前