Cakephp 模型自身相关，双向

我有一个人员表，其中人员通过id与其他人员关联。我认为这应该使用单独的表来完成，这是此类关系的标准，但我希望在查看单个记录时能够检索关联人员，而不管此记录存储为哪个键。例如：

table: people
id | first_name | last_name

table: people_associations
id | person_one_id | person_two_id

model: person
$hasMany = array(
    "Associates" => array(
        "className" => "Person",
        "foreignKey" => ????
    )
);

---

如何使

关联

引用关系，无论foreignKey是

person\u one\u id

还是

person\u two\u id

，并在一个整洁的数组中返回所有结果

我相信我成功地实现了一个解决方案。关键部分是使用适当的finderQuery来检查user_关联表中与用户相关的字段，并重新排列“first_id”和“second_id”字段，以确保Cake能够仅使用一个外键字段链接所有关联（本例中为“first_id”）

请注意，我使用了以下表格：

table: users
id | name

table: user_associations
id | first_id | second_id

1。定义用户关联模型

class UserAssociation extends AppModel {

    public $belongsTo = array(
        'Second' => array(
            'className' => 'User',
            'foreignKey' => 'second_id',
        )
    );
}

class User extends AppModel {

    //fields definition skipped for brevity

    public $hasMany = array(
        'UserAssociations' => array(
            'className' => 'UserAssociation',
            'foreignKey' => 'first_id',
            'finderQuery' => 'SELECT * FROM (SELECT UserAssociations.id, UserAssociations.first_id, UserAssociations.second_id 
                FROM user_associations as UserAssociations 
                WHERE (UserAssociations.first_id = {$__cakeID__$})
                UNION 
                SELECT UserAssociations2.id, UserAssociations2.second_id as first_id, UserAssociations2.first_id as second_id 
                FROM user_associations as UserAssociations2 
                WHERE (UserAssociations2.second_id = {$__cakeID__$}) ) as UserAssociations '
        )
    );
}

2。定义用户模型

class UserAssociation extends AppModel {

    public $belongsTo = array(
        'Second' => array(
            'className' => 'User',
            'foreignKey' => 'second_id',
        )
    );
}

class User extends AppModel {

    //fields definition skipped for brevity

    public $hasMany = array(
        'UserAssociations' => array(
            'className' => 'UserAssociation',
            'foreignKey' => 'first_id',
            'finderQuery' => 'SELECT * FROM (SELECT UserAssociations.id, UserAssociations.first_id, UserAssociations.second_id 
                FROM user_associations as UserAssociations 
                WHERE (UserAssociations.first_id = {$__cakeID__$})
                UNION 
                SELECT UserAssociations2.id, UserAssociations2.second_id as first_id, UserAssociations2.first_id as second_id 
                FROM user_associations as UserAssociations2 
                WHERE (UserAssociations2.second_id = {$__cakeID__$}) ) as UserAssociations '
        )
    );
}

3。结果

现在，当我运行以下示例查询时：

$this->User->recursive = 2;
$this->set('user_data', $this->User->read());

我将用户关联作为结果的一部分，并提供相关人员记录-这是视图中捕获的var_dump（$user_data）输出：

array (size=3)
  'User' => 
    array (size=2)
      'id' => string '1' (length=1)
      'name' => string 'John Doe' (length=8)
  'UserAssociations' => 
    array (size=2)
      0 => 
        array (size=4)
          'id' => string '1' (length=1)
          'first_id' => string '1' (length=1)
          'second_id' => string '18' (length=2)
          'Second' => 
            array (size=2)
              ...
      1 => 
        array (size=4)
          'id' => string '2' (length=1)
          'first_id' => string '1' (length=1)
          'second_id' => string '17' (length=2)
          'Second' => 
            array (size=2)
              ...

---

希望这有帮助

即使使用

finderQuery

选项，我也尝试了许多关系，但这非常困难。你有没有想过创建两个不同的关系，然后将两个数组合并在一起？@arilia我想这可能就是我的想法。我可以用两种方式保存它（person\u one\u id=1，person\u two\u id=2，然后：person\u one\u id=2，person\u two\u id=1）。不过，我在联接表上还有其他字段，所以它必须在编辑（保存两个关系）和删除（删除两个关系）时执行此操作，但我认为这不会太难。@RandyHall请告诉我这是否适用于您。我会的，这需要做很多工作。我会在未来几天的某个时候实施它，让你知道它是如何进行的！不过看起来不错，谢谢。