CakePHP中有许多模型

这是我的基本设置。。。家庭有很多学生有很多学生

如果注册为空，是否有办法排除学生？这是我的查找方法

    $options = array( 
        'order' => array('Family.family_last_name'),
        'group' => 'Family.id',
        'contain' => array(
            'Student', 'Student.Enrollment'
        ),
        'joins' => array(
            array(
                'table' => 'students',
                'alias' => 'Student',
                'type' => 'left',
                'conditions' => array(
                    'Family.id = Student.family_id'
                )
            ),
            array(
                'table' => 'enrollment',
                'alias' => 'Enrollment',
                'type' => 'left',
                'conditions' => array(
                    'Enrollment.student_id = Student.id'
                )
            )
        ),
        'conditions' => array(
            'Enrollment.status =' => 'withdrawn'
        )
    );

    $enrollment = $this->Family->find( 'all', $options);

这是它返回的数组。我怎样才能拆下杰克

    [Student] => Array
            (
                [0] => Array
                    (
                        [id] => 92
                        [first_name] => Jack
                        [Enrollment] => Array
                            (
                            )

                    )

                [1] => Array
                    (
                        [id] => 93
                        [first_name] => Jill
                        [Enrollment] => Array
                            (
                                [0] => Array
                                    (
                                        [id] => 99
                                        [student_id] => 93
                                        [grade] => 4
                                    )

                            )

                    )
              )

---

当您加入注册时，请摆脱左侧的加入。将其改为内部连接

$options = array( 
    'order' => array('Family.family_last_name'),
    'group' => 'Family.id',
    'contain' => array(
        'Student', 'Student.Enrollment'
    ),
    'joins' => array(
        array(
            'table' => 'students',
            'alias' => 'Student',
            'type' => 'left',
            'conditions' => array(
                'Family.id = Student.family_id'
            )
        ),
        array(
            'table' => 'enrollment',
            'alias' => 'Enrollment',
            'type' => 'inner',
            'conditions' => array(
                'Enrollment.student_id = Student.id'
            )
        )
    ),
    'conditions' => array(
        'Enrollment.status =' => 'withdrawn'
    )
);

$enrollment = $this->Family->find( 'all', $options);

---

我不明白当你有可包含的模型时为什么要使用连接。顺便说一句，我发现了这个解决方案：它是有效的，但我不认为这是最好的方法

在您的

系列中

型号

public $hasMany = array
(
    'Student' => array(
        'conditions' => array('Student.id IN (SELECT DISTINCT student_id FROM enrollments)')
    )
);

或者，如果愿意，您可以仅在需要时使用

Family->bindModel(array(
    'hasMany' => array (
            'Student' => array(
                'conditions' => array('Student.id IN (SELECT DISTINCT student_id FROM enrollments)')
        )
    )
)

---

不。尝试了之后，它就忽略了注册。status=drawn不应该是

家庭

和

学生

之间的连接，而应该是

内部连接？

我实际上尝试了所有可能的连接组合LOL！有没有人在包含和连接一起工作时遇到过任何问题？谢谢Arilia，Containeable忽略了遥远的关联，我需要能够根据这些关联过滤结果。我会试试看它是否有效。