Cocoa touch 异步请求iOS 6的NSURLConnection状态代码

当前正在使用sendAsynchronous from NSURLConnection发出post和get请求，但无法在响应中获取状态代码。大多数帖子建议使用NSURLConnection及其委托方法，据我所知，它们也是异步的

我不明白委托如何将信息发送回调用方法（最终需要数据的方法）。sendAsynchronous方法具有我正在使用的回调

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我是新手，谢谢你的帮助

当您使用

sendAsynchronousRequest:queue:completionHandle

方法时，我将尝试在该上下文中回答：

[NSURLConnection sendAsynchronousRequest:request 
                                   queue:queue 
                       completionHandler:
    ^(NSURLResponse *response, NSData *data, NSError *error) {

    // This will get the NSURLResponse into NSHTTPURLResponse format
    NSHTTPURLResponse* httpResponse = (NSHTTPURLResponse*)response;

    // This will Fetch the status code from NSHTTPURLResponse object
    int responseStatusCode = [httpResponse statusCode];

    //Just to make sure, it works or not
    NSLog(@"Status Code :: %d", responseStatusCode);
}];

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当您使用

sendAsynchronousRequest:queue:completionHandle

方法时，我将尝试在该上下文中回答：

[NSURLConnection sendAsynchronousRequest:request 
                                   queue:queue 
                       completionHandler:
    ^(NSURLResponse *response, NSData *data, NSError *error) {

    // This will get the NSURLResponse into NSHTTPURLResponse format
    NSHTTPURLResponse* httpResponse = (NSHTTPURLResponse*)response;

    // This will Fetch the status code from NSHTTPURLResponse object
    int responseStatusCode = [httpResponse statusCode];

    //Just to make sure, it works or not
    NSLog(@"Status Code :: %d", responseStatusCode);
}];

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我有一个包装器类，它使这变得非常简单，并保持代码干净：

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我有一个包装器类，它使这项工作变得非常简单，并保持代码整洁：