Compiler errors Arduino初学者问题
我对Arduino非常陌生,还没有尝试过一些例子。我在使用以下代码时遇到了一些问题:Compiler errors Arduino初学者问题,compiler-errors,arduino,Compiler Errors,Arduino,我对Arduino非常陌生,还没有尝试过一些例子。我在使用以下代码时遇到了一些问题: #include <ctype.h> #include <Arduino.h> #include "Telegraph.h" //#include <Telegraph.h> char* LETTERS[] = { ".-", "-...", "-.-.", "-..", ".", // A-E "..-.", "--.", "....", "..",
#include <ctype.h>
#include <Arduino.h>
#include "Telegraph.h"
//#include <Telegraph.h>
char* LETTERS[] = {
".-", "-...", "-.-.", "-..", ".", // A-E
"..-.", "--.", "....", "..", ".---", // F-J
"-.-", ".-..", "--", "-.", "---", // K-O
".--.", "--.-", ".-.", "...", "-", // P-T
"..-", "...-", ".--", "-..-", "-.--", // U-Y
"--.." // Z
};
char* DIGITS[] = {
"-----", ".----", "..---", "...--", //0-3
"....-", ".....", "-....", "--...", //4-7
"---..", "----." //8-9
};
Telegraph::Telegraph(const int outputPin, const int ditLength){
_outputPin = outputPin;
_ditLength = ditLength;
_dahLength = dahLength;
pinMode(_outputPin, OUTPUT);
}
void Telegraph::outputCode(const char* code){
for(int i=0; i<strlen(code); i++){
if( code[i] == '.' )
dit();
else
dah();
}
}
void Telegraph::dit(){
Serial.print(".");
outputSymbol(_ditLength);
}
void Telegraph::dah(){
Serial.print("-");
outputSymbol(_dahLength);
}
void Telegraph::outputSymbol(const int length){
digitalWrite(_outputPin, HIGH);
delay(length);
digitalWrite(_outputPin, LOW);
delay(length);
}
void Telegraph::sendMessage(const char* message){
for(int i=0; i < strlen(message); i++){
const char currentChar = toupper(message[i]);
if( isalpha(currentChar) ){
outputCode(LETTERS[currentChar - 'A']);
delay(_dahLength);
}else if(isdigit(currentChar) ){
outputCode(DIGITS[currentChar - '0']);
delay(_dahLength);
}else if(currentChar = ' '){
Serial.print(" ");
delay(_ditLength * 7);
}
}
Serial.println();
}
很抱歉,如果这个问题太笼统,但正如我提到的,我是一个新手,不完全理解代码
Telegraph.cpp:6:15:错误:“字母”声明中有两种或更多数据类型
在其他地方,符号字母
已经定义。也许在Telegraph.h
中?你得去找找
Telegraph.cpp: In constructor ‘Telegraph::Telegraph(int, int)’:
Telegraph.cpp:24:18: error: ‘dahLength’ was not declared in this scope
有关守则:
_dahLength = dahLength;
是的,dahLength
没有定义。也许您想将其作为另一个参数添加到构造函数中
Telegraph.cpp: In member function ‘void Telegraph::sendMessage(const char*)’:
Telegraph.cpp:58:18: error: ‘LETTERS’ was not declared in this scope
关于这个问题,请参见上文。解决第一个问题,并长期忽略这个问题
Telegraph.cpp:63:30: error: assignment of read-only variable ‘currentChar’
这是由于
}else if(currentChar = ' '){
我确定您要使用=
而不是=
}else if(currentChar = ' '){