访问内存映射I/O 我对嵌入式系统编程非常陌生，我只需要学习如何通过C++代码来操纵给定的。p>

鉴于：

电机1映射到0x60000000

电机2映射到0x50000000

以下是当前32位寄存器的定义

REGISTER NAME            |     BYTE OFFSET        |     NOTES
----------------------------------------------------------------------
motor_interrupt               0x00                 service interrupts

motor_status                  0x01                 enable on demand access to status elements
motor_command                 0x02                 enable command of the motor



REGISTER NAME           |   NAME   |  BITS   | ACCESS TYPE   | DESC 
----------------------------------------------------------------------------------

motor_interrupt_register
                           CLOSED      0          R/W         high when motor transitions to CLOSED position
                           OPEN        1          R/W         high when motor transitions to OPEN position
                           RESERVED    2.31       N/A         reserved for future use

motor_status        

                           SPEED       0.2         R          speed in counts/seconds
                           STATE        3          R          current state of motor
                           POSITION    4.13        R          current position of the motor
                           RESERVED    14.31       n/a         reserved for future use

<>我发现很难用给定的方法看到一个C++代码，在这里我知道我需要访问RealStestNoX并设置它们的位来执行特定的任务或者读取登记名来获得状态。p> 我认为如果它在C++代码中使用，我会更理解它。给定的是一个自动门系统（我没有写按钮的详细信息）。是否需要访问C++中的RealStestIONE或ByTeTeOffice？p>

---

非常感谢您的帮助

C/C++读取中断/状态寄存器示例：

volatile uint32_t * const motor1 = (uint32_t *)0x60000000; // base addresses for motors 1 and 2
volatile uint32_t * const motor2 = (uint32_t *)0x50000000;

enum  // register offsets from base address
{
    motor_interrupt, // 0x00 - service interrupts
    motor_status,    // 0x01 - enable on demand access to status elements
    motor_command    // 0x02 - enable command of the motor
}

// read status/interrupt registers

uint32_t current_int_1 = motor1[motor_interrupt];
uint32_t current_int_2 = motor2[motor_interrupt];

uint32_t current_status_1 = motor1[motor_status];
uint32_t current_status_2 = motor2[motor_status];

motor1[motor_command] = 0x8000 | (0x12 << 6) | 0x01;
motor2[motor_command] = 0x0;

类似于将32位值写入命令寄存器：

volatile uint32_t * const motor1 = (uint32_t *)0x60000000; // base addresses for motors 1 and 2
volatile uint32_t * const motor2 = (uint32_t *)0x50000000;

enum  // register offsets from base address
{
    motor_interrupt, // 0x00 - service interrupts
    motor_status,    // 0x01 - enable on demand access to status elements
    motor_command    // 0x02 - enable command of the motor
}

// read status/interrupt registers

uint32_t current_int_1 = motor1[motor_interrupt];
uint32_t current_int_2 = motor2[motor_interrupt];

uint32_t current_status_1 = motor1[motor_status];
uint32_t current_status_2 = motor2[motor_status];

motor1[motor_command] = 0x8000 | (0x12 << 6) | 0x01;
motor2[motor_command] = 0x0;

---

motor1[motor_command]=0x8000 |（0x12，谢谢你，有什么可以让我更清楚的文章/书吗？有很多关于嵌入式编程的书-在标题中找一些带有“embedded”、“programming”和“C”的东西。最好在地址处找一个结构。
struct motor{unsigned int interrupt，status，command}
。让一切看起来更美好。@重复数据消除器：使用结构可能会导致对齐、填充等问题。在这样一个简单的情况下可能会很好，但一般来说，在内存映射I/O方面，我更喜欢上面这样的可预测性和确定性。@fireflieslive非常适合学习微控制器编程，即使您是C/C++的初学者。它使用飞思卡尔HC12作为示例，但所有MCU都以类似的方式工作。