C++ 使用数据结构和数组求和的问题

我有这个代码，有几个功能，我几乎完成了，我只是有困难找到我的程序的租金成本。 我的程序读取一个汽车和租赁成本的文本文件，如下所示：

2014 Toyota Tacoma 115.12 1
2012 Honda CRV 85.10 0
2015 Ford Fusion 90.89 0
2013 GMC Yukon 110.43 0
2009 Dodge Neon 45.25 1
2011 Toyota Rav4 65.02 1
2012 Mazda CX5 86.75 1
2016 Subaru Outback 71.27 0
2015 Ford F150 200.83 1
2010 Toyota Corolla 50.36 1

浮动字符是价格（租赁成本）

然而，我希望用户输入汽车号码（1-10）选择多少天，并输出租赁成本。我只是有问题，它将如何读取用户想要的汽车输入。这是我的主要代码，但我需要告诉你案例3是否需要工作

#include <iostream>
#include <fstream>

using namespace std;

struct car {
    int year;
    char make[10];
    char model[10];
    float price;
    int available;

} ;

void menu();

// Main Function
int main ()
{
// declare variables
int carAmount = 10;
int choice;
car carLib[carAmount];
char filename[10];
ifstream carInData;
float mostExpensive = 0;
int MostExpensiveIndex;
int count = 0;
int days;
int rentalCost = 0;
bool menu1 = false;

    //prompt user for input file
    cout << " Enter file name: ";
    cin >> filename;

    // Start loop menu
    while(menu1 = true){

    menu();

    carInData.open(filename);

    cin >> choice;

    if (carInData.is_open()) {
    // read list of names into array


       for (; count < carAmount; count++) {

        carInData >> carLib[count].year >> carLib[count].make >> carLib[count].model >> carLib[count].price >> carLib[count].available;

        }
    }

    switch (choice) {

   // Case 1 closes menu
    case 1:

    return 0;
    break;

    // Case 2 displays if car is available if 1, unavailable if 0
    case 2:

    // itterate through car array
    for(count = 0; count < carAmount; count++){

    // Displays if car is available or not 
    if (carLib[count].available == 1)
        cout << " Available ";
    else
        cout << " Unavailable ";

    // Display Cars
    cout << carLib[count].year << " " << carLib[count].make << " " << carLib[count].model << " " << carLib[count].price << "  " << "\n";
    }
    break;

    // Display only available cars
    case 3:

    // itterate through car array
    for(count = 0; count < carAmount; count++){

    // Displays only available cars
    if (carLib[count].available == 1){
        cout << " Available ";

    // Display Cars
    cout << carLib[count].year << " " << carLib[count].make << " " << carLib[count].model << " " << carLib[count].price << "  " << "\n";
      }
    }
    break;


    // Calculates  rental cost
    case 4:
    cout << " Enter car number and how many days " << "\n";
    cout << " Days: ";
    cin >> days;
    cout << "\n" << "Car: ";
    cin >> carLib[count].price;
    rentalCost += days*count;

    cout << " Rental Cost for " << days << " days is " << rentalCost << "\n";
    break;

    // Finds most expensive car
    case 5:

    MostExpensiveIndex = count;
    for (size_t carIndex = 0; carIndex < carAmount; ++carIndex) {

        if (carLib[carIndex].price <= mostExpensive) continue;
        mostExpensive = carLib[carIndex].price;
        MostExpensiveIndex = carIndex;

    }

    const car & carI = carLib[MostExpensiveIndex];

    cout << " Most Expensive car is: " << " " << carI.year << " " << carI.make << " " <<  carI.model << " "  << carI.price << "\n";

    break;



      }

    }

    return 0;
}


void menu()
{
    cout << " 1 - Exit program.\n";
    cout << " 2 - Show Cars\n"; 
    cout << " 3 - Show only available cars.\n";
    cout << " 4 - Rental Cost\n";
    cout << " 5 - Most Expensive Car\n";
}  

#包括
#包括
使用名称空间std；
结构车{
国际年；
charmake[10]；
char模型[10]；
浮动价格；
int可用；
} ;
无效菜单（）；
//主要功能
int main（）
{
//声明变量
int-carAmount=10；
智力选择；
carLib[carAmount]；
字符文件名[10]；
ifstream Carinanda；
float mostExpensive=0；
intmostexpensiveindex；
整数计数=0；
国际日；
int rentalCost=0；
bool menu1=假；
//提示用户输入文件
cout>文件名；
//开始循环菜单
while（menu1=true）{
菜单（）；
打开（文件名）；
cin>>选择；
如果（carinanda.is_open（））{
//将名称列表读入数组
对于（；计数>carLib[count]。年份>>carLib[count]。制造>>carLib[count]。型号>>carLib[count]。价格>>carLib[count]。可用；
}
}
开关（选择）{
//案例1关闭菜单
案例1：
返回0；
打破
//案例2显示1时车辆是否可用，0时车辆是否不可用
案例2：
//直通车阵列
用于（计数=0；计数cout除非我误解了代码的工作原理，否则我认为案例3可以正常工作。不过，您应该担心的是案例4

      case 4:
            cout << " Enter car number and how many days " << "\n";
            cout << " Days: ";
            cin >> days;
            cout << "\n" << "Car: ";
            cin >> carLib[count].price;  // WHY IS THE USER CHANGING THE PRICE?
            rentalCost += days*count;    // WHY IS THE PRICE "DAYS * (CAR ID #)"

            cout << " Rental Cost for " << days << " days is " << rentalCost << "\n";
            break;

案例4：
也许如果你修复了代码中随机的、随意的缩进，一旦用正确的、可读的、逻辑的缩进进行布局，一个简单的解决方案就会变得显而易见。@SamVarshavchik好的！谢谢！是的，我只是将我的租车费改为浮动，以获得确切的金额。我只是将每辆车登记到一个特定的数字，以便用户知道。还有用途假设r只是单独检查每辆车的租金。我注意到如果用户试图检查其他车，价格会比前一辆车高，这不是我想要的。
      case 4:
            cout << " Enter car number and how many days " << "\n";
            cout << " Days: ";
            cin >> days;
            cout << "\n" << "Car: ";
            cin >> count ;
            // Note the decrement of 'count' by one, since you expect the user
            // to enter a number 1-10
            // Should probably include a check that the 'count' is valid
            rentalCost += days*carLib[count-1].price;

            cout << " Rental Cost for " << days << " days is " << rentalCost << "\n";
            break;