C++ 结构和文件

我已经制作了文本文件studenti.txt

盖蒂斯·利特涅克斯1993年6月15日v

Vizma Kalesnica 20.08.1991 s

卡特里娜萨伯恩6.12.1992南部

哈拉尔德·伯克夫斯基1989年2月1日v

Jezups Martinovs 02.05.1990 v

Vizma Zigurde 16.09.1988 s

Stasija Balode 12.12.1993 s

Jānis Bērziņš13.03.1992 v

Zigurds Ritms 16.05.1990 v

Pauls Zirdzins 12.11.1989 v

Zane Skarbule 28.12.1990年代

Aiga Bulle 11.08.1993 s

Andrejs Fomkins 11.06.1989 v

Maikls Dzordans 08.01.1988 v

我想读取文件并在c程序输出中打印它

我的代码是：

 #include <stdio.h>
 #include <conio.h>
 #include <string.h>
 #include <windows.h>
 #include <ctype.h>
 #define N 16
 int main()
 {
 FILE *fails_st;

 struct date
 { int da_year;
   int da_month;
   int da_day;
 };

 struct studenti
 {
 int Nr;
 char name[25];
 char surname[25];
 struct date dzd;
 char dzimums[1]; 
 } students[N];

 int i, j;
 system("cls");

 fails_st = fopen("studenti.txt", "r");
 for(i=0; i<N; i++)
 {
  fscanf(fails_st, "%d", &students[i].Nr);
  fgets(students[i].name, sizeof students[i].name, fails_st);
  fgets(students[i].surname, sizeof students[i].surname, fails_st);
  fscanf(fails_st, "%d", &students[i].dzd.da_day);
  fscanf(fails_st, "%d", &students[i].dzd.da_month);
  fscanf(fails_st, "%d", &students[i].dzd.da_year);
  fgets(students[i].dzimums, sizeof students[i].dzimums, fails_st);
  }
 fclose(fails_st);


 system("cls");

 printf("Student list\n");
 for(i=0; i<N; i++)
 printf("%d%s%s%d%d%d%s\n", students[i].Nr, 
 students[i].name, students[i].surname, 
 students[i].dzd.da_day,students[i].dzd.da_month,students[i].dzd.da_year,students[i].dzimums);
 getch();
 return 0;
 }

从使用

fgets（）

逐行读取开始

如果第一个字符是数字，则使用

strtol

转换为数字

使用

strtok

断行-将字符串拆分为以点和空格分隔的标记

编辑：请按照上述步骤找到实现，以将文件读入结构。想法是使用

fgets（）

读取每一行，并在所需的分隔符处使用

strtok

对其进行解析

    struct date
    { int da_year;
      int da_month;
      int da_day;
    };

    struct studenti
    {
      int Nr;
      char name[25];
      char surname[25];
      struct date dzd;
      char dzimums;
    } students[N];


    int main()
    {
       FILE *fails_st;
       char line[100];
       char *ptk; char * end; int i;

       fails_st = fopen("studenti.txt", "r");
       for(i=0; i < N && fgets(line, sizeof(line), fails_st) != NULL; i++)
       {
         students[i].Nr = strtol(line, &end, 10);

         ptk = strtok(line, " ");
         ptk = strtok(NULL, " ");
         strcpy(students[i].name, ptk);

         ptk = strtok(NULL, " ");
         strcpy(students[i].surname, ptk);

         ptk = strtok(NULL, ".");
         end = (ptk + strlen(ptk));
         students[i].dzd.da_day = strtol(ptk, &end, 10);

         ptk = strtok(NULL, ".");
         end = (ptk + strlen(ptk));
         students[i].dzd.da_month = strtol(ptk, &end, 10);

         ptk = strtok(NULL, " ");
         end = (ptk + strlen(ptk));
         students[i].dzd.da_year = strtol(ptk, &end, 10);

         ptk = strtok(NULL, " ");
         students[i].dzimums = *ptk;
       }
       fclose(fails_st);

       printf("Student list\n");
       for(i=0; i<N; i++)
       printf("%d. %s %s %d.%d.%d %c\n", students[i].Nr, students[i].name, 
              students[i].surname, students[i].dzd.da_day, 
              students[i].dzd.da_month, students[i].dzd.da_year, 
              students[i].dzimums);
       return 0;
    }

结构日期 {国际年； 国际大牛月； 国际日； }; 结构学生 { 国际天然气公司； 字符名[25]； 查氏[25]； 结构日期dzd； 查尔·季姆； }学生[N]； int main（） { 文件*失败\u st； 字符行[100]； 字符*ptk；字符*end；int i； 未通过测试=fopen（“studenti.txt”、“r”）； 对于（i=0；i对于（i=0；i

fgets

不是这样工作的）您确定您的学生希望成为StackOverflow的特色人物吗？

    struct date
    { int da_year;
      int da_month;
      int da_day;
    };

    struct studenti
    {
      int Nr;
      char name[25];
      char surname[25];
      struct date dzd;
      char dzimums;
    } students[N];


    int main()
    {
       FILE *fails_st;
       char line[100];
       char *ptk; char * end; int i;

       fails_st = fopen("studenti.txt", "r");
       for(i=0; i < N && fgets(line, sizeof(line), fails_st) != NULL; i++)
       {
         students[i].Nr = strtol(line, &end, 10);

         ptk = strtok(line, " ");
         ptk = strtok(NULL, " ");
         strcpy(students[i].name, ptk);

         ptk = strtok(NULL, " ");
         strcpy(students[i].surname, ptk);

         ptk = strtok(NULL, ".");
         end = (ptk + strlen(ptk));
         students[i].dzd.da_day = strtol(ptk, &end, 10);

         ptk = strtok(NULL, ".");
         end = (ptk + strlen(ptk));
         students[i].dzd.da_month = strtol(ptk, &end, 10);

         ptk = strtok(NULL, " ");
         end = (ptk + strlen(ptk));
         students[i].dzd.da_year = strtol(ptk, &end, 10);

         ptk = strtok(NULL, " ");
         students[i].dzimums = *ptk;
       }
       fclose(fails_st);

       printf("Student list\n");
       for(i=0; i<N; i++)
       printf("%d. %s %s %d.%d.%d %c\n", students[i].Nr, students[i].name, 
              students[i].surname, students[i].dzd.da_day, 
              students[i].dzd.da_month, students[i].dzd.da_year, 
              students[i].dzimums);
       return 0;
    }