C++ 为什么赢了'；我的十进制到二进制输出不是反向的吗？

我正在使用while循环进行一些简单的十进制到二进制的转换，我意识到循环的输出需要反转，我通过创建一个stringstream，然后将生成的int移动到一个stringstream，该stringstream将其转换为字符串，然后反转字符串的顺序以获得正确的二进制值来实现这一点。。。但是当我实际运行代码时，在所有的东西前面都有一个随机的1或0

#include <iostream>
#include <sstream>
#include <algorithm>

int main() {
    std::stringstream ss;
    int decimal;
    int binary;
    std::cout<< "\n Please enter decimal value: ";
    std::cin >> decimal;
    std::cout << "\n The binary equivalent of " << decimal << " is ";
    while(decimal > 0 ) {
        binary = decimal % 2;

        decimal/= 2;

        std::cout << binary;

    }
    ss << binary;
    std::string binary_string = ss.str();
    std::reverse(binary_string.begin(), binary_string.end());
    std::cout << binary_string;
}

对于12：

Please enter decimal value: 12

The binary equivalent of 12 is 00111

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有两个问题

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行

ss额外的位来自

ss << binary;
string binary_string = ss.str();
reverse(binary_string.begin(), binary_string.end());
cout << binary_string;

ss请提供一个。
int decimal;
int binary;
cout<< "\n Please enter decimal value: ";
cin >> decimal;
cout << "\n The binary equivalent of " << decimal << " is ";
while(decimal > 0 ) {
    binary = decimal % 2;

    decimal/= 2;
    ss << binary;

}

string binary_string = ss.str();
reverse(binary_string.begin(), binary_string.end());
cout << binary_string;

}

ss << binary;
string binary_string = ss.str();
reverse(binary_string.begin(), binary_string.end());
cout << binary_string;