C++ 让循环找出解决方案？
问题: 一个人携带所有物品需要多少次？每人每次可携带“携带重量”千克的重量 我的解决方案：C++ 让循环找出解决方案？,c++,C++,问题: 一个人携带所有物品需要多少次？每人每次可携带“携带重量”千克的重量 我的解决方案： int main() { int a = 40; // 1st item weight int b = 35; // 2nd item weight int c = 20; // 3rd item weight int maxItemWeight = a; // Max weight item. int times; // Times to carry all the item
int main()
{
int a = 40; // 1st item weight
int b = 35; // 2nd item weight
int c = 20; // 3rd item weight
int maxItemWeight = a; // Max weight item.
int times; // Times to carry all the items
int carryWeight; //How much weight a person can carry at once
cin >> carryWeight;
if (maxItemWeight > carryWeight)
cout << "It's impossible to carry all the items " << endl;
else {
if((a + b + c) <= carryWeight)
times = 1;
else if ((a+b) <=carryWeight && (a+c) <=carryWeight && (b+c) <=carryWeight)
times = 2;
else
times = 3;
cout << "Times to carry all the items: " << carryWeight << endl;
}
return 0;
}
intmain（）
{
int a=40；//第一项重量
int b=35；//第二项重量
int c=20；//第三项重量
int maxItemWeight=a；//最大重量项。
int times；//携带所有项目的时间
int carryWeight；//一个人一次能承受多少重量
cin>>携带量；
如果（maxItemWeight>carryWeight）
cout您似乎在询问是否可以使用数组来允许携带任意数量的“项目”。答案是肯定的：
std::vector<int> item_weights;
unsigned int item_count = 0;
std::cout << "Enter item count: ";
std::cin >> item_count; // I'll leave the error checking to you to implement
for (unsigned int i = 0; i < item_count; ++i)
{
std::cout << "Enter weight for item " << (i + 1) << ": ";
unsigned int w = 0;
std::cin >> w; // again error checking should be added
item_weights.push_back(w);
}
// insert code to retrieve maximum weight that can be carried here
unsigned int max_weight = std::max_element(item_weights.begin(), item_weights.end());
unsigned int total_weight = std::accumulate(item_weights.begin(), item_weights.end(), 0);
// insert your code to determine the number of times it would take to carry all items here
std:：向量项的权重；
无符号整数项计数=0；
std:：cout>item_count；//我将把错误检查留给您来实现
for（无符号整数i=0；i