将数组传递到C++中的函数？[彩票号码] 我正在用C++制作一个彩票游戏。 我创建了一个名为GetLottoPicks的函数，它要求用户输入7个数字。 我有另一个函数叫做GenWinNums，它可以生成7个随机数

问题是，它会连续7次生成以下内容：-858993460

我相信我对WinningNums[]的论点做出了贡献，但显然不是吗

多谢各位

int main()
{
string name;
int choice;
int user_picked[7];
int chosen_lotto[7];

cout << "LITTLETON CITY LOTTO MODEL:" << endl;
cout << "---------------------------" << endl;
cout << " 1) Play Lotto " << endl;
cout << " Q) Quit Program " << endl;
cout << " Please make a selection: ";
cin >> choice;

if (choice == 1)
{
    cout << "\n Please enter your name: ";
    cin >> name;

    getLottoPicks(user_picked);
    GenWinNums(chosen_lotto);

    for(int i = 0; i < 7; i++)
    {
        cout << chosen_lotto[i];    
    }

    for(int i = 0; i < 7; i++)
    {
        cout << user_picked[i];
    }
}

else if (choice == 'Q' || 'q')
{
    exit(0);
}

else 
{
    cout << "That is not a valid choice." << endl;
}

 system("PAUSE");
 return 0;
 }

 int getLottoPicks(int UserTicket[])
 {   
const int amount = 7;
UserTicket[amount];
int ticket = UserTicket[amount];

for (int i = 0; i < amount; i++)
{
    cout << "\n Please enter number " << i + 1 << ":";
    cin >> UserTicket[i];

    while (UserTicket[i] < 1 || UserTicket[i] > 40)

    {
        cout << "Your selection cannot be less than 1 and/or greater than 40. Try Again." << endl;
        cin >> UserTicket[i];
    }

if(i > 0)
    {
        for(int check = 0; check < i; check++)
        {
            while(UserTicket[i] == UserTicket[check])
            {
                cout << "You cannot use the same lotto number twice. Try again: " << endl;
                cin >> UserTicket[i];
            }
        }
}

}

return ticket;
 }

 int GenWinNums(int WinningNums[])
 {
const int amount = 7;
int numbers[amount];
int ticket = WinningNums[amount];

for(int i = 0; i < amount; i++)
{
    numbers[i] = (rand() % 40) + 1;

    while(numbers[i] < 1 || numbers[i] > 40)
    {
        numbers[i] = (rand() % 10) + 1;
    }
    if(i > 0)
    {
        for(int check = 0; check < i; check++)
        {
            while(numbers[i] == numbers[check])
            {
                numbers[i] = (rand() % 10) + 1;
            }
        }
    }
}
return ticket;
 }

---

看起来您从未在例程中为WinningNums数组赋值，这可能解释了为什么您总是得到相同的数字

---

我建议删除数字数组并直接使用WinningNums生成随机数。

看起来您在例程中从未为WinningNums数组赋值，这可能解释了为什么您总是得到相同的数字

---

我建议删除数字数组，直接使用WinningNums生成您的随机数。

为了好玩，这里有大量修复方法。我不打算一一列举。基本上：

通过引用传递固定大小的数组，以避免不安全的使用 严格检查输入错误，并在单个循环中执行 几个错误的数组分配，要么什么也不做，要么阻止调用者看到结果。。。 使用char作为输入类型，这样Q将永远得到匹配，并且更喜欢aa切换而不是重复的ifs 下面是一个更典型的C++风格解决方案，包括赢或输的检查 读者练习：为你的兰德生成器添加种子，或者在上一张中奖彩票中粘贴此彩票非常简单：

演示运行的输出还显示了错误处理：

LITTLETON CITY LOTTO MODEL:
---------------------------
 1) Play Lotto 
 Q) Quit Program 
Please make a selection: 1

 Please enter your name: me

 Please enter number 1:34

 Please enter number 2:7

 Please enter number 3:16

 Please enter number 4:18

 Please enter number 5:24

 Please enter number 6:24
Duplicate entry 24
 Please enter number 6:7
Duplicate entry 7
 Please enter number 6:37

 Please enter number 7:whoops
Bad input 'whoops' discarded
 Please enter number 7:what was the last number again?
Bad input 'what' discarded
 Please enter number 7:Bad input 'was' discarded
 Please enter number 7:Bad input 'the' discarded
 Please enter number 7:Bad input 'last' discarded
 Please enter number 7:Bad input 'number' discarded
 Please enter number 7:Bad input 'again?' discarded
 Please enter number 7:27
User ticket:    7; 16; 18; 24; 27; 34; 37; 
Winning ticket: 7; 16; 18; 24; 27; 34; 36; 
Result of draw: WINNER

更典型的C++解决方案

---

只是为了好玩，这里有大量的补丁。我不打算一一列举。基本上：

通过引用传递固定大小的数组，以避免不安全的使用 严格检查输入错误，并在单个循环中执行 几个错误的数组分配，要么什么也不做，要么阻止调用者看到结果。。。 使用char作为输入类型，这样Q将永远得到匹配，并且更喜欢aa切换而不是重复的ifs 下面是一个更典型的C++风格解决方案，包括赢或输的检查 读者练习：为你的兰德生成器添加种子，或者在上一张中奖彩票中粘贴此彩票非常简单：

演示运行的输出还显示了错误处理：

LITTLETON CITY LOTTO MODEL:
---------------------------
 1) Play Lotto 
 Q) Quit Program 
Please make a selection: 1

 Please enter your name: me

 Please enter number 1:34

 Please enter number 2:7

 Please enter number 3:16

 Please enter number 4:18

 Please enter number 5:24

 Please enter number 6:24
Duplicate entry 24
 Please enter number 6:7
Duplicate entry 7
 Please enter number 6:37

 Please enter number 7:whoops
Bad input 'whoops' discarded
 Please enter number 7:what was the last number again?
Bad input 'what' discarded
 Please enter number 7:Bad input 'was' discarded
 Please enter number 7:Bad input 'the' discarded
 Please enter number 7:Bad input 'last' discarded
 Please enter number 7:Bad input 'number' discarded
 Please enter number 7:Bad input 'again?' discarded
 Please enter number 7:27
User ticket:    7; 16; 18; 24; 27; 34; 37; 
Winning ticket: 7; 16; 18; 24; 27; 34; 36; 
Result of draw: WINNER

更典型的C++解决方案

---

信不信由你，你不知道如何使用数组！您调用了WinningNums[amount]，其中amount=7，数组的大小为7！出界了！好吧，也许这与问题无关。这是关于你需要知道的。信不信由你，你不知道如何使用数组！您调用了WinningNums[amount]，其中amount=7，数组的大小为7！出界了！好吧，也许这与问题无关。这是你需要知道的，GenWinNums会生成7个介于1和40之间的随机数。您看到的其他两个循环让您感到困惑，您只需确保没有重复的循环，并且它们不大于40且小于1。WinningNums[]参数是否应该包含计算后的7个随机数？是的，它应该包含生成的7个数字。好，然后，在某个时候，您需要分配给该数组的元素，即WinningNums[i]=numbers[i]，或者干脆去掉numbers数组，直接使用WinningNums参数。很好，我会试试。非常感谢您的帮助。GenWinNums会生成7个介于1和40之间的随机数。您看到的其他两个循环让您感到困惑，您只需确保没有重复的循环，并且它们不大于40且小于1。WinningNums[]参数是否应该包含计算后的7个随机数？是的，它应该包含生成的7个数字。好，然后，在某个时候，您需要分配给该数组的元素，即WinningNums[i]=numbers[i]，或者干脆去掉numbers数组，直接使用WinningNums参数。很好，我会试试。非常感谢你的帮助。

#include <string>
#include <iostream>
#include <algorithm>
#include <iterator>
#include <set>

const size_t amount = 7;

typedef std::set<int> ticket_t;

ticket_t getLottoPicks()
{
    ticket_t ticket;
    while (ticket.size() < amount)
    {
        std::cout << "\n Please enter number " << (ticket.size()+1) << ":";

        int entry;
        if(std::cin >> entry)
        {
            if(entry >= 1 && entry <= 40)
            {
                if (ticket.end() != ticket.find(entry))
                    std::cout << "Duplicate entry "  << entry;
                else
                    ticket.insert(entry);
            } else
                std::cout << "Entry out of range [1..40]: "  << entry;

            continue;
        }

        std::cin.clear();
        std::string discard;
        std::cin >> discard;
        std::cout << "Bad input '" << discard << "' discarded";
    }
    return ticket;
}

ticket_t genWinNums()
{
    ticket_t ticket;
    while (ticket.size() < amount)
        ticket.insert(rand() % 40 + 1);
    return ticket;
}

std::ostream& operator<<(std::ostream& os, ticket_t const& t)
{
    std::copy(t.begin(), t.end(), std::ostream_iterator<int>(os, "; "));
    return os;
}

int main()
{
    std::cout << "LITTLETON CITY LOTTO MODEL:" << std::endl;
    std::cout << "---------------------------" << std::endl;
    std::cout << " 1) Play Lotto "             << std::endl;
    std::cout << " Q) Quit Program "           << std::endl;
    std::cout << "Please make a selection: ";
    char choice;
    std::cin >> choice;

    switch(choice)
    {
        case '1':
            {
                std::cout << "\n Please enter your name: ";
                std::string name;
                std::cin  >> name;

                const ticket_t user    = getLottoPicks();
                const ticket_t winning = genWinNums();

                std::cout << "User ticket:    " << user    << "\n";
                std::cout << "Winning ticket: " << winning << "\n";

                // check win?
                bool ok = 0 == std::lexicographical_compare(
                        user.begin(), user.end(),
                        winning.begin(), winning.end());

                std::cout << "Result of draw: " << (ok? "WINNER":"No luck") << "\n";
            }
        case 'Q': case 'q':
            return 0;
        default:
            std::cout << "\n That is not a valid choice." << std::endl;
    }

    std::cin.ignore(1<<24,'\n');
    std::cout << "\n Press enter...";
    std::string dummy;
    std::getline(std::cin, dummy);
}