C++ 执行lua c++；函数多次执行会导致lua脚本失败，且值为nil

Lua脚本

algdata={lua_obj1=-1,lua_obj2=-1}
return algdata

c++代码

初始化

更新循环

int result;
printstackDump(L);
lua_newtable(L);
int tableindex = 1;
lua_pushnumber(L, tableindex++);
lua_pushnumber(L, fdcur->var1);
lua_rawset(L, -3);
lua_pushnumber(L, tableindex++);
lua_pushnumber(L, fdcur->var2);
lua_rawset(L, -3);
lua_pushnumber(L, tableindex++);
lua_pushnumber(L, fdcur->var3);
lua_rawset(L, -3);

lua_setglobal(L, "data");
result = lua_pcall(L, 0, 1, 0);
if (result) {
    fprintf(stderr, "Failed to run script: %s\n", lua_tostring(L, -1));
}
ar->lua_obj1 = GetNumberFromLua(L, "lua_obj1");
ar->lua_obj2 = GetNumberFromLua(L, "lua_obj2");
ar->lua_obj3 = GetNumberFromLua(L, "lua_obj3");
printstackDump(L);
lua_pop(L, 1);

第一次更新： 第一个堆栈转储（第一行）=“功能” 第二个堆栈转储（最后一行-pop之前）=“表”

第二次更新： 第一次堆垛（第一行）=''（空）

---

lua_pcall失败=尝试调用nil值

lua_pcall已被替换为

int luaL_dofile (lua_State *L, const char *filename);
Loads and runs the given file. It is defined as the following macro:

     (luaL_loadfile(L, filename) || lua_pcall(L, 0, LUA_MULTRET, 0))
It returns 0 if there are no errors or 1 in case of errors.

如果需要，这将在内存中重新加载文件，否则调用pcall

Remove

lua_pop（L，1）来自更新循环
int luaL_dofile (lua_State *L, const char *filename);
Loads and runs the given file. It is defined as the following macro:

     (luaL_loadfile(L, filename) || lua_pcall(L, 0, LUA_MULTRET, 0))
It returns 0 if there are no errors or 1 in case of errors.