C++ 删除并查找的stl错误，如果

我使用vector student来表示多态性，因为我从基类学生中派生了本地学生和国际学生。现在的问题是我的函子有错误。我有两种删除方法。两者都不起作用。我该如何解决这个问题？哪种删除方法更好

void deleteStudent(vector <clsStudent*>& student)
{
    cout << "Enter student name to delete";
    student.erase(remove(student.begin(), student.end(), nameToDelete), student.end());

    vector <clsStudent*>::iterator it = student.begin();
    while (it != student.end())
    {
         if (*it == nameToDelete)
         {
             it = student.erase(it);
         }
         else{
             ++it;
         }
     }
}

void searchStudent(const vector <clsStudent*>& s)
{
    string searchName;

    cout << "\nEnter student name to search for. Press [Q] to terminate." << endl;
    cin >> searchName;


    if (s.size() == 0)
        cout << "There is 0 student in the database.";

    while(searchName != "q")
    {
        vector<clsStudent*>::iterator it = std::find_if(s.begin(),
                                                s.end(),
                                                MatchName(searchName)); <---- ERROR here
}

int main()
{
    char choice;
    clsUniversityProgram objProgram[3];
    for (int x = 0; x < 3; x++)
    {
        objProgram[x].programInfo();
    }
    vector <clsStudent*> student;

    do
    {
    cout <<"\nPress [A] to add new student"
        << "\nPress [L] to list existing stundet"
        << "\nPress [M] to modify existing student"
        << "\nPress [O] to sort student data by name"
        << "\nPress [W] to write students data to file"
        << "\nPress [R] to read students data from file"
        << "\nPress [D] to delete a student"
        << "\nPress [X] to exit"
        << "\nEnter your choice: " << endl;
        choice = toupper(getch());

        switch(choice){
        case 'A':
            addStudents(student, objProgram);
            break;
        case 'L':
        {
            for(int x = 0; x < student.size(); x++)
            {
                student[x]->printStudentDetails();
                student[x]->print();
            }
            break;
        }
        case 'M':
            // modify
        case 'O':
            sortStudentbyName(student);
            break;
        case 'W':
            // write
            break;
        case 'R':
            // read
            break;
        case 'D':
            deleteStudent(student);
            break;
        case 'X':
            return 0;
        default:
            cerr << "Invalid input!" << endl;
            break;
        }
   } while (choice != 'L'
            && choice != 'M'
            && choice != 'O'
            && choice != 'W'
            && choice != 'R'
            && choice != 'D');
    return 0;
}
struct MatchName
    {
      MatchName(string& searchName) : s_(searchName) {}
      bool operator()(const clsStudent* student) const
      {
        return student->getName() == s_;
      }
     private:
      string s_;
    };

错误

错误：从“uuu gnu_cxx:：uu normal_iterator”转换为非标量类型“std:：vector:：iterator{aka uuu gnu cxx:：uu normal_iterator}”请求

find_if的问题是s是对向量的常量引用，但返回的迭代器是非常量的，因此尝试更改为：

vector<clsStudent*>::const_iterator it = std::find_if(...)

您尚未发布要删除的调用的错误，但我怀疑这是因为您确实打算写：

remove_if(student.begin(), student.end(), MatchName(nameToDelete))

---

您报告的错误来自searchStudent方法

---

你的向量是常量，所以你不能使用迭代器，而是使用常量迭代器

你真的应该发布MatchName。为什么要在main中包含io代码，而不是在发生错误的行上使用MatchName的签名？为什么不包括一份实际错误的副本？我将您的问题编辑为在代码中使用`字符，这样字符就不会被视为HTML，请在发布问题之前使用预览，以确保其格式正确，并请多花几秒钟写出正确的英语，“我不是im。对不起，忘了火柴的名字了。”乔纳森·韦克利，谢谢。下次我会记住这一点。

remove_if(student.begin(), student.end(), MatchName(nameToDelete))