C++ 当GoogleTestFixture没有默认构造函数时,如何在其中定义变量?
我有以下几点C++ 当GoogleTestFixture没有默认构造函数时,如何在其中定义变量?,c++,googletest,C++,Googletest,我有以下几点 #include <semsim/Subject.h> #include <semsim/Triple.h> #include "gtest/gtest.h" class TripleTests : public ::testing::Test { public: std::string subject_str; semsim::Subject subject; void SetUp() override {
#include <semsim/Subject.h>
#include <semsim/Triple.h>
#include "gtest/gtest.h"
class TripleTests : public ::testing::Test {
public:
std::string subject_str;
semsim::Subject subject;
void SetUp() override {
subject_str = "./MyModel#metaid_0";
subject = semsim::Subject(subject_str);
}
};
TEST_F(TripleTests, TestSubjectMetaId) { // this line causes the error
std::cout << subject << std::endl;
}
因此,我的问题是:在不需要定义默认构造函数的情况下,如何在TripleTest
类中创建subject对象,以便在TEST\F
函数中使用它?或者有必要在Suject
中设置默认构造函数,以便在测试夹具中创建一个构造函数吗
作为参考,主题
标题如下所示:
class Subject {
private:
std::string metaId;
public:
explicit Subject(std::string metaId) : metaId(std::move(metaId)) {};
const std::string &getMetaId() const;
bool operator==(const Subject &rhs) const;
bool operator!=(const Subject &rhs) const;
friend std::ostream &operator<<(std::ostream &os, const Subject &subject);
};
}
导致
Constructor for 'TripleTests' must explicitly initialize the member 'subject' which does not have a default constructor. Isn't the line `this->subject = s` initialising the member `subject`?
您必须使用fixture的构造函数而不是
SetUp()
来初始化初始化器列表中的成员:
class TripleTests : public ::testing::Test {
public:
std::string subject_str;
semsim::Subject subject;
TripleTests()
: subject_str("./MyModel#metaid_0")
, subject(subject_str)
{
}
};
Constructor for 'TripleTests' must explicitly initialize the member 'subject' which does not have a default constructor. Isn't the line `this->subject = s` initialising the member `subject`?
class TripleTests : public ::testing::Test {
public:
std::string subject_str;
semsim::Subject subject;
TripleTests()
: subject_str("./MyModel#metaid_0")
, subject(subject_str)
{
}
};