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C++ 此语句在三重嵌套循环中执行多少次?_C++_Algorithm_Math_Time Complexity - Fatal编程技术网

C++ 此语句在三重嵌套循环中执行多少次?

C++ 此语句在三重嵌套循环中执行多少次?,c++,algorithm,math,time-complexity,C++,Algorithm,Math,Time Complexity,这是我的问题 for(i=1;i<=n;i++) for(j=1;j<=i;j++) for(k=1;k<=j;k++) x++; for(i=1;i您正在查找以下总和的值: Sum(i from 1 to n) Sum (j from 1 to i) Sum (k from 1 to j) 1 从内到外工作: Sum(i from 1 to n)

这是我的问题

for(i=1;i<=n;i++)
    for(j=1;j<=i;j++)
        for(k=1;k<=j;k++)
            x++;

for(i=1;i您正在查找以下总和的值:

  Sum(i from 1 to n)
      Sum (j from 1 to i)
          Sum (k from 1 to j)
              1
从内到外工作:

  Sum(i from 1 to n)
      Sum (j from 1 to i)
          Sum (k from 1 to j)
              1
= Sum(i from 1 to n)
      Sum (j from 1 to i)
          j

= Sum(i from 1 to n)
      i(i + 1) / 2
从这里,我们得到

求和(i从1到n)i(i+1)/2

=(1/2)和(i从1到n)(i2+i)

=(1/2)(和(i从1到n)i2+和(i从1到n)i)

=(1/2)(n(n+1)(2n+1)/6+n(n+1)/2)

然后你可以试着简化多项式,得到一个干净、精确的值,如果你只需要渐近上界,它就是Θ(n3)

据报道,这是

n3/6+n2/2+n/3


希望这有帮助!

首先找出2D的情况。它是单纯形的体积,不是吗?+1用于获得与我相同的答案!:)也许你应该添加一个更封闭的形式:n(n+1)(2n+4)/12。