C++ 如何在序列中找到一个数字的位置？

假设我有一个序列： 国际序号[4][4]； 那么，假设seq[1][2]=8； 序列中没有其他值产生8。

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如果我想找到一个序列的值并打印出它是哪一个，例如1,2，并使x=1和y=2，我该怎么做？您搜索的内容。查看每个元素，看看它是否包含所需的值。如果序列中存在可以利用的模式，则可以跳过已知不能包含所搜索值的元素，从而加快搜索速度。这正是我要查找的内容。非常感谢。

int x,j;
for (int i = 0; i < 4; i++) // looping through row
{
    for(int j = 0; j < 4; j++) //looping through column
    {
       if (seq[i][j] == 8) //if value matches
       {
           x = i; y = j;   //set value
           i = 4;          //set i to 4 to exit outer for loop
           break;          //exit inner for loop
       }
    }
}

int numberBeingSearchedFor = *Any Value Here*;
int array[*numRows*][*numColumns*];
int firstOccuranceRow = -1, firstOccuranceColumn = -1;

for(int i = 0; i < numRows; ++i)
{
    for(int j = 0; j < numColumns; ++j)
    {
        if(array[i][j] == numberBeingSearchedFor)
        {
            firstOccuranceRow = i;
            firstOccuranceColumn = j;
            i = numRows; //Credit to other answer, I've never seen that :) It's cool
            break;
        }
    }
}

if(firstOccuranceRow == -1 || firstOccuranceColumn == -1)
{
   //Item was not in the array
}