我的程序跳过getline(cin、CustInfo)并在CustomerInfo函数中转到City。我怎样才能修好它? 我只是学习C++。我想,也许,cin.ignore会有帮助。我想你把它放在getline前面了
以下是一个示例程序:我的程序跳过getline(cin、CustInfo)并在CustomerInfo函数中转到City。我怎样才能修好它? 我只是学习C++。我想,也许,cin.ignore会有帮助。我想你把它放在getline前面了,c++,getline,C++,Getline,以下是一个示例程序: CustAcc CustomerInfo( ){ CustAcc CustInfo; //Define a local structure //Customer Information cout<<"Name: "; getline(cin, CustInfo.Name); cout<<"City: "; cin
CustAcc CustomerInfo( ){
CustAcc CustInfo; //Define a local structure
//Customer Information
cout<<"Name: ";
getline(cin, CustInfo.Name);
cout<<"City: ";
cin>>CustInfo.Address.City;
cout<<"Enter the state where you live: ";
cin>> CustInfo.Address.State;
cout<<"Enter the ZIP code of your area: ";
cin>> CustInfo.Address.ZIP;
cout<<"Enter your telephone number without hyphens and space (e.g. 6060543013) : ";
cin>> CustInfo.Tel_Num;
CustInfo.Acc_Balance = 0;
do{
cout<<"Enter the balance in your account (balance below 0 is not accepted):";
cin>>CustInfo.Acc_Balance;
}while(CustInfo.Acc_Balance < 0);
cout<<"Enter the date of last Payment. Use no space or article to distinguish between month, date and year.(e.g 092016): ";
cin>> CustInfo.Date_of_LastPayment;
return CustInfo;
}
这个答案解释了为什么会发生这种情况:
int main()
{
char ch;
int number;
cout << "Enter a number: ";
cin >> number;
cin.ignore();
cout << "Enter a character: ";
ch = cin.get();
cout << "Thank you!\n";
return 0;
}