C++ 如何修复我的C++；箱子开关菜单？

我的学校项目有问题。我正在学校服务器上使用UNIX中的VIM编写它。当我在项目中插入记录时，姓氏将被跳过。名字和姓氏同时被提示，而不等待姓氏接收输入。见下文：

我的菜单是这样做的：

菜单
（一） n插入新记录
（五十） ast名称搜索
（S） 将数据库保存到文件
（R） 从文件读取数据库
（Q） 尤特

输入选项：i

插入选定的新记录

请输入员工的姓氏： 请输入员工的名字：

它在姓氏之前跳过了

我需要在某处添加cout.flush（）吗？当我在姓氏部分下面添加cout.flush（）时，我得到以下错误：

unixapps1:Lab1> make
g++ -o LSL lab1.cpp Employee.cpp
lab1.cpp: In function âEmployee createRecord()â:
lab1.cpp:41: error: âstruct std::istreamâ has no member named âflushâ

我的中的菜单代码如下：

int main() {

  cout << "\n"
       << "************************************************************\n"
       << "Remember: Search for TODO's in VI before submitting project!\n"
       << "************************************************************\n\n";

  char menu_choice;
  string fileName;

  // Create a database
  LinkedSortedList<Employee> database;

  while (true) {
    // Display menu
    cout << "MENU\n"
     << "(I)nsert new record\n"
     << "(L)ast name search\n"
     << "(S)ave database to a file\n"
     << "(R)ead database from a file\n"
     << "(Q)uit\n\n";

    cout << "Enter choice: ";
    cin >> menu_choice;
    cout << endl;

    switch (toupper(menu_choice)) {

    case 'I':
      cout << "Insert new record selected\n\n";
      {database.insert(createRecord());}
      break;

    case 'L':
      cout << "Last name search selected\n\n";
      // TODO call function to search by last name
      // TODO call search for Last Name
      // TODO Print all matches found
      {string searchVal = "";
    database.find(searchVal);}
      break;

    case 'S':
      cout << "Save database to a file selected\n\n";
      // TODO call function to save database to file
      // File I/O Save to file
      cout << "Please enter a file name: " << endl;
      cin >> fileName;
      {char* file = (char*) fileName.c_str();
    writeFile(file, database);}
      break;

    case 'R':
      cout << "Read database from a file selected\n\n";
      // TODOOA call function to read database from file
      // File I/O Read file
      cout << "Please enter a file name: " << endl;
      cin >> fileName;
      {char* file = (char*) fileName.c_str();
    readFile(file, database);}
      break;

    case 'Q':
      exit(EXIT_SUCCESS);

      // default case:
    default:
      cout << "Invalid choice!\n\n"
       << "##### Please try again #####\n\n";
      break;

      cin >> menu_choice;
    }
  }
  return 0;
}

---

看起来输入流中仍然有一个换行符或其部分

---

尝试使用

std:：istream:：ignore（）

来吃掉输入流中剩余的字符。

您是否尝试使用

cin.get（）

而不是

cout.flush（）

？

具体来说，尝试添加

cin.ignore（std:：numeric_limits:：max（），'\n'）

@SethCarnegie:是的，只是提醒人们换行符可以是两个字符：回车“\r”和换行符；取决于平台或操作系统。：-）@ThomasMatthews我甚至认为windows不再使用

\r\n

。

// Create the record to be inserted into the employee database
Employee createRecord() {
  // Temporary variables for getting input from user
  string stringInput = "";
  int intInput = 0;

  Employee newEmployee;

  cout << "Please enter employee's Last Name: " << endl;
  getline(cin, stringInput);
  newEmployee.setLastName(stringInput);

  cout << "Please enter employee's First Name: " << endl;
  getline(cin, stringInput);
  newEmployee.setFirstName(stringInput);

  cout << "Please enter employee's ID: ";
  getline(cin, stringInput);
  stringstream myStream(stringInput);
  myStream >> intInput;
  newEmployee.setId(intInput);

  cout << "Please enter employee's Salary: ";
  getline(cin, stringInput);
  myStream >> intInput;
  newEmployee.setSalary(intInput);

  cout << "Please enter employee's Department: ";
  getline(cin, stringInput);
  newEmployee.setDepartment(stringInput);

  cout << "Please enter employee's Phone Number: ";
  getline(cin, stringInput);
  newEmployee.setPhoneNumber(stringInput);

  cout << "Please enter employee's Address: ";
  getline(cin, stringInput);
  newEmployee.setAddress(stringInput);

  cout << "Please enter employee's Hire Date: ";
  getline(cin, stringInput);
  newEmployee.setHireDate(stringInput);
}