C# 如何根据用户输入使图片框从可见变为不可见?
我正在用C#制作一个Enigma模拟器应用程序。除此之外,我还试图制作它的光板,它基本上是一个键盘,用来照亮反射器返回的字母。现在,我的想法是添加26个带有黄色字母图像的图片框,并在每个图片框的顶部添加26个带有灰色字母图像的其他图片框 如果用户键入0个字母,则灰色字母是可见的。当用户键入一个字母时,enigma将对其进行解码并根据其设置返回另一个字母,该字母应在键盘上打开(字母的黄色图像),然后在下一个字母到达时关闭(灰色图像) 下面的代码显示了我是如何做到这一点的,但我不知道如何让它们一个接一个地进行,而不是一次完成。任何关于如何实现这一效果的帮助或建议都将受到欢迎C# 如何根据用户输入使图片框从可见变为不可见?,c#,picturebox,C#,Picturebox,我正在用C#制作一个Enigma模拟器应用程序。除此之外,我还试图制作它的光板,它基本上是一个键盘,用来照亮反射器返回的字母。现在,我的想法是添加26个带有黄色字母图像的图片框,并在每个图片框的顶部添加26个带有灰色字母图像的其他图片框 如果用户键入0个字母,则灰色字母是可见的。当用户键入一个字母时,enigma将对其进行解码并根据其设置返回另一个字母,该字母应在键盘上打开(字母的黄色图像),然后在下一个字母到达时关闭(灰色图像) 下面的代码显示了我是如何做到这一点的,但我不知道如何让它们一个接
StringBuilder ciphertext = new StringBuilder(txtCiphertext.Text);
int i = 0;
while (i < ciphertext.Length)
{
if (ciphertext[i] == (char)Keys.A)
{
Aoff.Visible = false;
Aon.Visible = true;
}
else if (ciphertext[i] == (char)Keys.B)
{
Boff.Visible = false;
Bon.Visible = true;
}
else if (ciphertext[i] == (char)Keys.C)
{
Coff.Visible = false;
Con.Visible = true;
}
else if (ciphertext[i] == (char)Keys.D)
{
Doff.Visible = false;
Don.Visible = true;
}
else if (ciphertext[i] == (char)Keys.E)
{
Eoff.Visible = false;
Eon.Visible = true;
}
else if (ciphertext[i] == (char)Keys.F)
{
Foff.Visible = false;
Fon.Visible = true;
}
else if (ciphertext[i] == (char)Keys.G)
{
Goff.Visible = false;
Gon.Visible = true;
}
else if (ciphertext[i] == (char)Keys.H)
{
Hoff.Visible = false;
Hon.Visible = true;
}
else if (ciphertext[i] == (char)Keys.I)
{
Ioff.Visible = false;
Ion.Visible = true;
}
else if (ciphertext[i] == (char)Keys.J)
{
Joff.Visible = false;
Jon.Visible = true;
}
else if (ciphertext[i] == (char)Keys.K)
{
Koff.Visible = false;
Kon.Visible = true;
}
else if (ciphertext[i] == (char)Keys.L)
{
Loff.Visible = false;
Lon.Visible = true;
}
else if (ciphertext[i] == (char)Keys.M)
{
Moff.Visible = false;
Mon.Visible = true;
}
else if (ciphertext[i] == (char)Keys.N)
{
Noff.Visible = false;
Non.Visible = true;
}
else if (ciphertext[i] == (char)Keys.O)
{
Ooff.Visible = false;
Oon.Visible = true;
}
else if (ciphertext[i] == (char)Keys.P)
{
Poff.Visible = false;
Pon.Visible = true;
}
else if (ciphertext[i] == (char)Keys.Q)
{
Qoff.Visible = false;
Qon.Visible = true;
}
else if (ciphertext[i] == (char)Keys.R)
{
Roff.Visible = false;
Ron.Visible = true;
}
else if (ciphertext[i] == (char)Keys.S)
{
Soff.Visible = false;
Son.Visible = true;
}
else if (ciphertext[i] == (char)Keys.T)
{
Toff.Visible = false;
Ton.Visible = true;
}
else if (ciphertext[i] == (char)Keys.U)
{
Uoff.Visible = false;
Uon.Visible = true;
}
else if (ciphertext[i] == (char)Keys.V)
{
Voff.Visible = false;
Von.Visible = true;
}
else if (ciphertext[i] == (char)Keys.W)
{
Woff.Visible = false;
Won.Visible = true;
}
else if (ciphertext[i] == (char)Keys.X)
{
Xoff.Visible = false;
Xon.Visible = true;
}
else if (ciphertext[i] == (char)Keys.W)
{
Woff.Visible = false;
Won.Visible = true;
}
else if (ciphertext[i] == (char)Keys.Z)
{
Zoff.Visible = false;
Zon.Visible = true;
}
i++;
}
StringBuilder-ciphertext=新的StringBuilder(txtCiphertext.Text);
int i=0;
while(i
当用户使用按键输入时,您可以验证用户的输入。当用户按下某个键时,将引发此事件,并由一个函数处理该事件,并执行此函数中的代码。您还可以使用switch
而不是倍数if
语句
首先创建处理程序函数:
private void textBox1_KeyPress(object sender, System.Windows.Forms.KeyPressEventArgs e)
{
switch (e.KeyChar)
{
case 'A':
Aoff.Visible = false;
Aon.Visible = true;
break;
case 'B':
Boff.Visible = false;
Bon.Visible = true;
break;
...
}
}
然后需要将函数与文本框
关联起来
如果您这样做,当用户按下文本框中的键时,将执行此功能,它将执行您需要的操作
我在这里留下了一些页面,您可以查看这些页面以获取更多信息
我的答覆是:
这并不是一个完整的解决方案,我只是在说正确的话
您可以使用文本框的按键事件捕获按下的按键
Dictionary<char, Tuple<PictureBox, string, string>> List = new
Dictionary<char, Tuple<PictureBox, string, string>>();
private void Form9_Load(object sender, EventArgs e)
{
//Reading both yellow and grey Imgs
string[] grey = Directory.GetFiles(@"C:\greyImgs");
string[] yellow = Directory.GetFiles(@"C:\yellowImgs");
//looping thought the controls in the groupbox which are PictureBoxs
for (int i = 0; i < groupBox1.Controls.Count; i++)
{
// Casting the controls as PictureBox
PictureBox pic = groupBox1.Controls[i] as PictureBox;
// Adding the grey imgs to PictureBoxx
pic.ImageLocation = grey[i];
// Populating the Dictionary
List.Add(Path.GetFileNameWithoutExtension(grey[i])[0], new Tuple<PictureBox, string, string>(pic, grey[i], yellow[i]));
}
}
private void textBox1_KeyPress(object sender, KeyPressEventArgs e)
{
// e.keychar returns the key that the user pressed
// So we Don't want the user to press a key we don't have so we perform a check
if (List.ContainsKey(e.KeyChar))
{
// Here we get the first item of the tuple which is the picturebox
// and we assign the yellow img being the third item in the tuple.
List[e.KeyChar].Item1.ImageLocation = List[e.KeyChar].Item3;
}
}