C# 如何在C中从XmlNode获取参数值#

如何获取XmlNode标记中的参数值。例如：

<weather time-layout="k-p24h-n7-1">
    <name>Weather Type, Coverage, and Intensity</name>
    <weather-conditions weather-summary="Mostly Sunny"/>
</weather>

天气类型、覆盖范围和强度

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我想获取节点“weather conditions”中参数“weather summary”的值

为了完整起见，还应给出.Net 3.5方式：

var node = xmldoc.SelectSingleNode("weather/weather-conditions");
var attr = node.Attributes["weather-summary"];

假定

XDocument doc = XDocument.Parse(@"<weather time-layout='k-p24h-n7-1'>
    <name>Weather Type, Coverage, and Intensity</name>
    <weather-conditions weather-summary='Mostly Sunny'/></weather>");

或

我会给你同样的答案

return doc.Element("weather").Element("weather-conditions").Attribute("weather-summary").Value;

return doc.Descendants("weather-conditions").First().Attribute("weather-summary").Value;