C#-使用后台工作程序从另一个类返回bool响应

我有一个WinForm，它有一个按钮，单击该按钮时，会调用另一个类中的方法将文本文件上载到Pastebin。代码最初工作正常，但在上传成功完成之前锁定了UI，因此我现在尝试使用后台工作程序完成此任务，以便UI保持响应

我在Visual Studio中遇到的错误是

将匿名函数转换为返回的无效委托无法返回值

。我看过类似的线程/谷歌，但不太明白这意味着什么，以及如何去纠正它

我的上传按钮代码：

private void btnUpload_Click(object sender, EventArgs e)
{
    this.btnUpload.Enabled = false;
    this.btnUpload.Text = "Uploading...";
    if (Pastebin.UploadLog())
    {
        Clipboard.SetText(Properties.Settings.Default.logUrl);
        MessageBox.Show("Your logfile has been uploaded to Pastebin successfully.\r\n" +
            "The URL to the Paste has been copied to your clipboard.", "Upload successful!", MessageBoxButtons.OK, MessageBoxIcon.Information);
    }
    else
    {
        MessageBox.Show("The upload of your logfile to Pastebin failed.", "Upload failed!", MessageBoxButtons.OK, MessageBoxIcon.Information);
    }
    this.btnUpload.Text = "Upload";
    this.btnUpload.Enabled = true;
}

完成上载的我的代码：

class Pastebin
    {
        public static bool UploadLog()
        {
            var upload = new BackgroundWorker();
            upload.DoWork += delegate
            { 
                Properties.Settings.Default.logUrl = "";
                Properties.Settings.Default.Save();

                System.Collections.Specialized.NameValueCollection Data = new System.Collections.Specialized.NameValueCollection();
                Data["api_paste_name"] = "RWC_Log_" + DateTime.Now.ToString() + ".log";
                Data["api_paste_expire_Date"] = "N";
                Data["api_paste_code"] = File.ReadAllText(Properties.Settings.Default.AppDataPath + @"\Logs\RWC.log");
                Data["api_dev_key"] = "017c00e3a11ee8c70499c1f4b6b933f0";
                Data["api_option"] = "paste";


                WebClient wb = Proxy.setProxy();

                try
                {
                    byte[] bytes = wb.UploadValues("http://pastebin.com/api/api_post.php", Data);

                    string response;
                    using (MemoryStream ms = new MemoryStream(bytes))
                    using (StreamReader reader = new StreamReader(ms))
                        response = reader.ReadToEnd();

                    if (response.StartsWith("Bad API request"))
                    {
                        Logging.LogMessageToFile("Failed to upload log to Pastebin: " + response);
                        return false;

                    }
                    else
                    {
                        Logging.LogMessageToFile("Logfile successfully uploaded to Pastebin: " + response);
                        Properties.Settings.Default.logUrl = response;
                        Properties.Settings.Default.Save();
                        return true;
                    }
                }
                catch (Exception ex)
                {
                    Logging.LogMessageToFile("Error uploading logfile to Pastebin: " + ex.Message);
                    return false;
                }
            };

            upload.RunWorkerAsync();

        }
    }

---

我建议您使用

async

函数，而不是

BackgroundWorker

。您可以使您的

UploadLog

函数

async

如下所示

public static async Task<bool> UploadLog()
    {


            Properties.Settings.Default.logUrl = "";
            Properties.Settings.Default.Save();

            System.Collections.Specialized.NameValueCollection Data = new System.Collections.Specialized.NameValueCollection();
            Data["api_paste_name"] = "RWC_Log_" + DateTime.Now.ToString() + ".log";
            Data["api_paste_expire_Date"] = "N";
            Data["api_paste_code"] = File.ReadAllText(Properties.Settings.Default.AppDataPath + @"\Logs\RWC.log");
            Data["api_dev_key"] = "017c00e3a11ee8c70499c1f4b6b933f0";
            Data["api_option"] = "paste";


            WebClient wb = Proxy.setProxy();

            try
            {
                byte[] bytes = wb.UploadValues("http://pastebin.com/api/api_post.php", Data);

                string response;
                using (MemoryStream ms = new MemoryStream(bytes))
                using (StreamReader reader = new StreamReader(ms))
                    response = reader.ReadToEnd();

                if (response.StartsWith("Bad API request"))
                {
                    Logging.LogMessageToFile("Failed to upload log to Pastebin: " + response);
                    return false;

                }
                else
                {
                    Logging.LogMessageToFile("Logfile successfully uploaded to Pastebin: " + response);
                    Properties.Settings.Default.logUrl = response;
                    Properties.Settings.Default.Save();
                    return true;
                }
            }
            catch (Exception ex)
            {
                Logging.LogMessageToFile("Error uploading logfile to Pastebin: " + ex.Message);
                return false;
            }

    }

---

我建议您使用

async

函数，而不是

BackgroundWorker

。您可以使您的

UploadLog

函数

async

如下所示

public static async Task<bool> UploadLog()
    {


            Properties.Settings.Default.logUrl = "";
            Properties.Settings.Default.Save();

            System.Collections.Specialized.NameValueCollection Data = new System.Collections.Specialized.NameValueCollection();
            Data["api_paste_name"] = "RWC_Log_" + DateTime.Now.ToString() + ".log";
            Data["api_paste_expire_Date"] = "N";
            Data["api_paste_code"] = File.ReadAllText(Properties.Settings.Default.AppDataPath + @"\Logs\RWC.log");
            Data["api_dev_key"] = "017c00e3a11ee8c70499c1f4b6b933f0";
            Data["api_option"] = "paste";


            WebClient wb = Proxy.setProxy();

            try
            {
                byte[] bytes = wb.UploadValues("http://pastebin.com/api/api_post.php", Data);

                string response;
                using (MemoryStream ms = new MemoryStream(bytes))
                using (StreamReader reader = new StreamReader(ms))
                    response = reader.ReadToEnd();

                if (response.StartsWith("Bad API request"))
                {
                    Logging.LogMessageToFile("Failed to upload log to Pastebin: " + response);
                    return false;

                }
                else
                {
                    Logging.LogMessageToFile("Logfile successfully uploaded to Pastebin: " + response);
                    Properties.Settings.Default.logUrl = response;
                    Properties.Settings.Default.Save();
                    return true;
                }
            }
            catch (Exception ex)
            {
                Logging.LogMessageToFile("Error uploading logfile to Pastebin: " + ex.Message);
                return false;
            }

    }

---

DoWork是一个事件处理程序，不能从事件处理程序返回任何内容。DoWork是一个事件处理程序，不能从事件处理程序返回任何内容。如果要使用BackgroundWorker，必须指定具有两个类似参数的委托。upload.DoWork+=委托（对象发送方，DoWorkEventArgs e）{}，然后在必要时设置

e.Result=true

，而不是返回值。感谢您的建议。这似乎现在运行，这是一个加号，但我似乎回到了我第一次遇到的问题，即在上传完成时UI被锁定。谢谢。正如我在评论中提到的，使用BackroungWorker可以获得相同的结果。只需将具有两个类似参数的委托添加到

upload.DoWork

事件

upload.DoWork+=delegate（对象发送方，doworkereventargs e）{}

然后在必要时使用

e.Result=true

或

e.Result=false

，而不是使用return语句。谢谢，错过了那个评论！我再试试看。：）当您想要得到在DoWork事件中设置的结果时，您应该像这样使用另一个BackgroundWorker事件

RunWorkerCompleted

upload.RunWorkerCompleted+=委托（对象发送方，RunWorkerCompletedEventArgs e）{Messagebox.Show（e.Result.ToString（））}

如果要使用BackgroundWorker，必须指定具有两个类似参数的委托。upload.DoWork+=委托（对象发送方，DoWorkEventArgs e）{}，然后在必要时设置

e.Result=true

，而不是返回值。感谢您的建议。这似乎现在运行，这是一个加号，但我似乎回到了我第一次遇到的问题，即在上传完成时UI被锁定。谢谢。正如我在评论中提到的，使用BackroungWorker可以获得相同的结果。只需将具有两个类似参数的委托添加到

upload.DoWork

事件

upload.DoWork+=delegate（对象发送方，doworkereventargs e）{}

然后在必要时使用

e.Result=true

或

e.Result=false

，而不是使用return语句。谢谢，错过了那个评论！我再试试看。：）当您想要得到在DoWork事件中设置的结果时，您应该像这样使用另一个BackgroundWorker事件

RunWorkerCompleted

upload.RunWorkerCompleted+=委托（对象发送方，RunWorkerCompletedEventArgs e）{Messagebox.Show（e.Result.ToString（））}