C# 在给定月份和年份的情况下,如何获取特定周中的一组日期?
如何获得给定月份和年份的特定周的日期 例如: 我的参数:C# 在给定月份和年份的情况下,如何获取特定周中的一组日期?,c#,asp.net,date,datetime,C#,Asp.net,Date,Datetime,如何获得给定月份和年份的特定周的日期 例如: 我的参数: June - 2013 - The second week 我希望结果集如下所示: 9-6-2013 10-6-2013 11-6-2013 12-6-2013 13-6-2013 我希望它从太阳开始到周四。我还没有真正测试过这一点,但我认为这或多或少符合您的要求: int year = 2013; int month = 6; int lookupWeek = 2;
June - 2013 - The second week
我希望结果集如下所示:
9-6-2013
10-6-2013
11-6-2013
12-6-2013
13-6-2013
我希望它从太阳开始到周四。我还没有真正测试过这一点,但我认为这或多或少符合您的要求:
int year = 2013;
int month = 6;
int lookupWeek = 2;
int daysInMonth = DateTime.DaysInMonth(year, month);
int weekCounter = 1;
List<DateTime> weekDays = new List<DateTime>();
for (int day = 1; day <= daysInMonth; day++)
{
DateTime date = new DateTime(year,month,day);
if(date.DayOfWeek == DayOfWeek.Sunday && day > 1) weekCounter++;
if(weekCounter == lookupWeek) weekDays.Add(date);
}
在我的图书馆里,我会:
从上个月底开始
在下一个星期天,你想循环多少次就循环多少次
从那里开始,产生天数,这样您就可以使用foreach循环:
因此:
这样的循环效率不高——你可以算出需要提前多少天——但更明显的是,这是正确的。你可以很容易地以一个错误结束,或者用一种更有效的方法回到上个月。当然,如果这很重要的话,你可以选择更加努力地提高效率。这种方法给出了一个月中某一周的天数:
static IEnumerable<string> DaysInWeek(int year, int month, int week)
{
var date = new DateTime(year, month, 1);
var calendar = new GregorianCalendar();
var firstWeek = calendar.GetWeekOfYear(date, CalendarWeekRule.FirstFullWeek, DayOfWeek.Sunday);
var days = calendar.GetDaysInMonth(year, month);
var daysInWeek = (from day in Enumerable.Range(0, calendar.GetDaysInMonth(year, month) - 1)
let dayDate = date.AddDays(day)
let week2 = calendar.GetWeekOfYear(dayDate, CalendarWeekRule.FirstFullWeek, DayOfWeek.Sunday) - firstWeek + 1
where week2 == week
select day + 1).ToList();
foreach (var d in daysInWeek) yield return string.Format("{0:00}-{1:00}-{2:0000}", d, month, year);
}
将是:
09-06-2013
10-06-2013
11-06-2013
12-06-2013
13-06-2013
注意:我已经编辑了代码。有一只小虫子;因为在许多月份,第一周和最后一周都不是完整的几周,而这一周的某些日子属于另一个月。如果您对客户端JavaScript路线感兴趣,那么可能值得一看,它允许以下内容:
// What date is next thursday?
Date.today().next().thursday();
// Add 3 days to Today
Date.today().add(3).days();
// Is today Friday?
Date.today().is().friday();
// Number fun
(3).days().ago();
// 6 months from now
var n = 6;
n.months().fromNow();
// Set to 8:30 AM on the 15th day of the month
Date.today().set({ day: 15, hour: 8, minute: 30 });
// Convert text into Date
Date.parse('today');
Date.parse('t + 5 d'); // today + 5 days
Date.parse('next thursday');
Date.parse('February 20th 1973');
Date.parse('Thu, 1 July 2004 22:30:00');
我发现自然语言语法“下周四”非常强大。试试这个
protected void button_click(object sender, EventArgs e)
{
DateTime dt = new DateTime(2013, 6, 1);
string[] dates = getDates(dt);
}
public string[] getDates(DateTime dt)
{
string[] result = new string[7]; ;
for (int i = getDay(dt.DayOfWeek.ToString()); i < 7; i++)
{
if (i == 0)
{
break;
}
else
{
dt = dt.AddDays(1);
}
}
for (int i = 0; i < 7; i++)
{
dt = dt.AddDays(1);
result[i] = dt.ToShortDateString();
}
return result;
}
public int getDay(string day)
{
switch (day)
{
case "Monday":
return 0;
case "Tuesday":
return 1;
case "Wednesday":
return 2;
case "Thursday":
return 3;
case "Friday":
return 4;
case "Saturday":
return 5;
case "Sunday":
return 6;
default:
return 0;
}
}## Heading ##
如果你热衷于使用linq,我几乎总是这样!,您可以这样做:
int year = 2013;
int month = 6;
int weekOfMonth = 2;
var dates = Enumerable.Range(1, DateTime.DaysInMonth(year, month))
.Select(day => new DateTime(year, month, day))
.GroupBy(g=> g.DayOfYear/7)
.ToList();
var week = dates.Min(g => g.Key) + weekOfMonth - 1;
var result = dates.Where(g=> g.Key.Equals(week)).Select(g => g.ToList());
你如何定义本周?总是从8号开始?总是从星期六开始?在ISO术语中,一年中的一周?我希望它从星期天开始到星期三,在我的示例中,这是第二个星期。那么,编写代码的问题到底是什么?弄清楚一周中哪一天是某一天?查找给定月份的第一天?递增天数直到找到满足条件的第一天?数到7?我写方法,但我认为这是针对我的情况,我想要一些一般的方式你说你想让Sun结婚,但你的例子显示Sun to Thu?更新了几次,使用了更清晰的变量名和一个星期编号的修正。我正要说StackOverflow先生在野田时间工作,他会推荐它的!:--1:试试这个,没有任何评论,这不是一个很好的答案格式,所以。
// What date is next thursday?
Date.today().next().thursday();
// Add 3 days to Today
Date.today().add(3).days();
// Is today Friday?
Date.today().is().friday();
// Number fun
(3).days().ago();
// 6 months from now
var n = 6;
n.months().fromNow();
// Set to 8:30 AM on the 15th day of the month
Date.today().set({ day: 15, hour: 8, minute: 30 });
// Convert text into Date
Date.parse('today');
Date.parse('t + 5 d'); // today + 5 days
Date.parse('next thursday');
Date.parse('February 20th 1973');
Date.parse('Thu, 1 July 2004 22:30:00');
protected void button_click(object sender, EventArgs e)
{
DateTime dt = new DateTime(2013, 6, 1);
string[] dates = getDates(dt);
}
public string[] getDates(DateTime dt)
{
string[] result = new string[7]; ;
for (int i = getDay(dt.DayOfWeek.ToString()); i < 7; i++)
{
if (i == 0)
{
break;
}
else
{
dt = dt.AddDays(1);
}
}
for (int i = 0; i < 7; i++)
{
dt = dt.AddDays(1);
result[i] = dt.ToShortDateString();
}
return result;
}
public int getDay(string day)
{
switch (day)
{
case "Monday":
return 0;
case "Tuesday":
return 1;
case "Wednesday":
return 2;
case "Thursday":
return 3;
case "Friday":
return 4;
case "Saturday":
return 5;
case "Sunday":
return 6;
default:
return 0;
}
}## Heading ##
int year = 2013;
int month = 6;
int weekOfMonth = 2;
var dates = Enumerable.Range(1, DateTime.DaysInMonth(year, month))
.Select(day => new DateTime(year, month, day))
.GroupBy(g=> g.DayOfYear/7)
.ToList();
var week = dates.Min(g => g.Key) + weekOfMonth - 1;
var result = dates.Where(g=> g.Key.Equals(week)).Select(g => g.ToList());