C# 如何将jquery、ajax和mysql结合使用？

我有一些代码。我想在我的代码中添加jquery和ajaxin。我试过了，但没有这样做

这里是我的jQuery代码

$(document).ready(function () {
    $('#btnGOlustur_Click').click(function () {
        var Pro_id = $('#drop_p').val(); //drop_p is combobox' name.
        var Ity_id = $('#drop_i').val();
        var Sta_id = $('#drop_s').val();
        document.write("basliyorrrr");

        $.ajax({
            type: 'POST',
            contentType: "application/json; charset=utf-8",
            url: 'GorevEkle.aspx/btnGOlustur_Click',
            data: "{'project_id':'" + Pro_id + "','status_id':'" + Sta_id + "','itype_id':'" + Ity_id + "'}",
            async: false,
            success: function (response) {
                $('#drop_p').val(''); $('#drop_i').val(''); $('#drop_s').val('');
                alert("Record saved successfully in database");
                document.write("dataabase e kaydedildi");
            },
            error: function () {
                alert("some problem in saving data");
            }
        });
    });
});

我的保存cs文件

[WebMethod]
[ScriptMethod]
protected void btnGOlustur_Click(object sender, EventArgs e)
{
    try
    {
        MySqlConnection con = new MySqlConnection(Globals.CONNECTION_STRING);
        con.Open();
        String UserId = Session["user_id"].ToString();
        int Pro_id = Convert.ToInt32(drop_p.SelectedValue);
        int Sta_id = Convert.ToInt32(drop_s.SelectedValue);
        int Ity_id = Convert.ToInt32(drop_i.SelectedValue);
        MySqlCommand cmd = new MySqlCommand("INSERT INTO issue (user_id, project_id, status_id, itype_id) values ('" + UserId + "','" + Pro_id + "','" + Sta_id + "','" + Ity_id + "')", con);
        cmd.ExecuteNonQuery();
        con.Close();
    }
    catch (Exception err)
    {
        lbl_hata.Text = "Error reading list of names. ";
        lbl_hata.Text += err.Message;
    }
    Response.Redirect("Profil.aspx");
}

这里是我的错误：

mscorlib.dll中首次出现“System.Threading.ThreadAbortException”类型的异常
mscorlib.dll中出现“System.Threading.ThreadAbortException”类型的异常，但未在用户代码中处理

---

您的代码中有几个错误

[WebMethod]应该是静态的才能调用它

将btnGOlustur\u单击逻辑移动到单独的静态方法

无法做出响应。在ajax上下文中重定向

钩住Request.Params中的值

综上所述,

[WebMethod]
[ScriptMethod]
public static string MyMethod()
{
    try
    {
        MySqlConnection con = new MySqlConnection(Globals.CONNECTION_STRING);
        con.Open();
        String UserId = HttpContext.Current.Session["user_id"].ToString();
        int Pro_id = HttpContext.Current.Request.Params["project_id"];
        //other values
        MySqlCommand cmd = new MySqlCommand("INSERT INTO issue (user_id, project_id, status_id, itype_id) values ('" + UserId + "','" + Pro_id + "','" + Sta_id + "','" + Ity_id + "')", con);
        cmd.ExecuteNonQuery();
        con.Close();
    }
    catch (Exception err)
    {
        return "error";
    }
    return "success";
}

然后你的jQuery

$(document).ready(function () {
    $('#btnGOlustur_Click').click(function (e) {
        var Pro_id = $('#drop_p').val(); //drop_p is combobox' name.
        var Ity_id = $('#drop_i').val();
        var Sta_id = $('#drop_s').val();


        $.ajax({
            type: 'POST',
            contentType: "application/json; charset=utf-8",
            url: 'GorevEkle.aspx/MyMethod',
            data: "{'project_id':'" + Pro_id + "','status_id':'" + Sta_id + "','itype_id':'" + Ity_id + "'}",
            async: false,
            success: function (response) {
                if(response=="success"){
                $('#drop_p').val(''); $('#drop_i').val(''); $('#drop_s').val('');
                alert("Record saved successfully in database");
                }
                else{
                 //handle error
                }
            },
            error: function () {
                alert("some problem in saving data");
            }
        });
    });
});

---

当我在这里使用static时，combobox和Session出现错误。@user3627624，请查找更新的答案。您还需要使用

我仍然有一些错误，这三行int Pro_id=HttpContext.Current.Request.Params[“project_id”]；int Sta_id=转换为NT32（下拉选择值）；int-Ity\u-id=转换为32（drop\u i.SelectedValue）；它没有看到组合框。@user3627624，您无法看到组合框，因为它没有发送viewstate，并且没有遵循整个页面生命周期。如果您不确定，请阅读有关使用jQuery和aspx页面方法的更多信息。还有一些将字符串转换为int的基本c#编程工具，等等，我的错误是，“非静态字段方法或属性需要一个对象引用。它在combobox中工作，但在静态中不工作。为什么？