C# 如何将函数的返回值赋给变量?

C# 如何将函数的返回值赋给变量?,c#,C#,也许这可以更清楚。该方法正在返回值…但在返回值后,我无法在程序的其余部分访问它。我对困难的部分发表了评论。 class CharacterStats { public int CharacterHitPoints() { int Health = 0; Random rnd = new Random(); Health = rnd.Next(30,70); return (Health);

也许这可以更清楚。该方法正在返回值…但在返回值后,我无法在程序的其余部分访问它。我对困难的部分发表了评论。

class CharacterStats
{
    public int CharacterHitPoints()
    {
        int Health = 0;            
        Random rnd = new Random();
        Health = rnd.Next(30,70);
        return (Health);
    }

    public int CharacterStrength()
    {
        int Strength = 0;
        Random rnd = new Random();
        Strength = rnd.Next(1,20);
        return (Strength);
    }
}

class ApplicationObject
{
    static void Main()
    {
      string CharName;
      string KeepStats;

      MonsterAttackRolls GoblinAttack = new MonsterAttackRolls();
      MonsterAttackRolls OrcAttack = new MonsterAttackRolls();
      MonsterAttackRolls OgreAttack = new MonsterAttackRolls();
      MonsterAttackRolls DragonAttack = new MonsterAttackRolls();

      MonsterHitPoints GoblinHealth = new MonsterHitPoints();
      MonsterHitPoints OrcHealth = new MonsterHitPoints();
      MonsterHitPoints OgreHealth = new MonsterHitPoints();
      MonsterHitPoints DragonHealth = new MonsterHitPoints();

      CharacterStats PlayerHealth = new CharacterStats();
      CharacterStats PlayerStrength = new CharacterStats();

      Console.WriteLine("Welcome to Realm, the top adventure game in the world!  Please enter the name of your character if you wish to continue:");
      CharName = Console.ReadLine();

      Console.WriteLine("Welcome {0} to Realm!  You will be given stats.  They may be good or they may be bad.\nYou only get 2 rolls for your stats though, so pick wisely!  From there you must fight 4 fearsome beasts.\n  If you survive, you will win the game.  If you die, well, you die.  Press any key to continue.", CharName);
      Console.ReadLine();

      Console.WriteLine("You will be given a strength number which augments your damage. Your strength can range from 1 - 20.\n A strength of 15 or over gives you a bonus to damage.  A strength of 5 or less gives you a penalty.   You will be start with a hit point number between 30-70.  Good luck!");
      Console.ReadLine();

      Console.WriteLine("Your first set of stats is:\n Health = {0}.\nYour strength is {1}.\nIf you would like to roll again press 1.  If you want to keep your stats press any other key.", PlayerHealth.CharacterHitPoints(), PlayerStrength.CharacterStrength());
      KeepStats =  Console.ReadLine();

      if (KeepStats == "1")
      {
          Console.WriteLine("So you want a second set of stats.  Okay.\n Your health is now: {0}.\n Your strength is now: {1}.", PlayerHealth.CharacterHitPoints(), PlayerStrength.CharacterStrength());
          Console.ReadLine();
      }



        Console.WriteLine("Okay {0} you are ready to go.  Good luck!\n.  Once again, your stats are:  Health: {1}\n Strength: {2}", CharName, //How do I access the return value? x 2?;
        Console.ReadLine();
    }







    }
}
注释就在上面的行中,这是我想要放置返回值的地方,并且可以访问程序的其余部分。

编辑:,因为您编辑的问题更清楚。我相信你正在寻找以下

您需要将返回值分配给代码中的某个变量,然后在Console.WriteLine中显示这些变量的值。否则,它们将丢失

有点像跟踪

int CharacterStrengthInt = PlayerStrength.CharacterStrength();
int CharacterHitPointsInt = PlayerHealth.CharacterHitPoints();
 if (KeepStats == "1")
      {
        Console.WriteLine("So you want a second set of stats.  Okay.\n Your health is now: {0}.\n Your strength is now: {1}."
       , CharacterHitPointsInt, CharacterStrengthInt);
          Console.ReadLine();
      }
你只要打个电话就可以了

int strength = characterStatsObject.CharacterStrength() 
创建CharacterStats对象后

CharacterStats objCS = new CharacterStats();
int CHP = objCS.CharacterHitPoints();
int CRS = objCS.CharacterStrength();

如果在MAIN子句中执行此操作,则可以使用这两个变量

var myVariable=Console.Readline()??请遵循网络上的任何C#教程。我不是在阅读网络教程。我被课本上的方法第五章难住了。我的搜索结果是Steve在C、Python中找到了一些例子,但在C#中没有。无论如何,我将重新阅读我关于方法的一章。这在我看来相当复杂。好吧,那么我需要在函数中还是在我的主代码中创建对象呢?这不起作用。这将再次调用该函数。它没有将前一个方法的返回值赋给Main()中的变量。@MatthewOttewell,我不知道您是如何尝试的。但在您自己的代码中,您将从方法向变量赋值。参见第行
Health=rnd.Next(30,70)我编辑了我的文章,以显示程序的完整代码(除了另外两个与此问题无关的类)。这样做效果更好。它的工作并不完美,但我看到返回值在第一次返回时存储为变量。诚然,当我再次调用该函数时,它不会更新值。这没有道理……但这是一个很好的开始。我必须在之前而不是之后声明变量。我认为返回的值附加了一些我可以访问的内存。我想不是。
CharacterStats objCS = new CharacterStats();
int CHP = objCS.CharacterHitPoints();
int CRS = objCS.CharacterStrength();