C# ASP MVC API控制器组合分类结果
在ASP MVC Api上,我有树命名的函数来检索数据,但我想将它们组合到一个请求样式中。下面是代码C# ASP MVC API控制器组合分类结果,c#,asp.net,asp.net-mvc,asp.net-mvc-4,C#,Asp.net,Asp.net Mvc,Asp.net Mvc 4,在ASP MVC Api上,我有树命名的函数来检索数据,但我想将它们组合到一个请求样式中。下面是代码 [ActionName("Styles")] public IEnumerable<StyleDTO> GetStyles() { return from s in db.styles select new StyleDTO() { Name = s.Name, StyleId = s.StyleId }; } [ActionName("Label
[ActionName("Styles")]
public IEnumerable<StyleDTO> GetStyles()
{
return from s in db.styles
select new StyleDTO() { Name = s.Name, StyleId = s.StyleId };
}
[ActionName("Labels")]
public IEnumerable<LabelDTO> GetLabels()
{
return from l in db.Labels
select new LabelDTO() { Name = l.Name, LabelId = l.LabelId , image = l.image};
}
[ActionName("Commodity")]
public IEnumerable<CommodityDTO> GetCommodity()
{
return from c in db.Commodities
select new CommodityDTO() { CommodityId = c.CommodityId, CreateDate = c.CreateDate, Name = c.Name, Varieties = ( from v in c.Varieties select new VarietyDTO()
{
CommodityId = v.CommodityId, Name = v.Name, VarietyId = v.VarietyId
}) };
}
[ActionName(“样式”)]
公共IEnumerable GetStyles()
{
以db.styles格式从s返回
选择newstyledto(){Name=s.Name,StyleId=s.StyleId};
}
[ActionName(“标签”)]
公共IEnumerable GetLabels()
{
从数据库标签中的l返回
选择newlabeldto(){Name=l.Name,LabelId=l.LabelId,image=l.image};
}
[行动名称(“商品”)]
公共IEnumerable GetCommodity()
{
以db.商品从c返回
选择new CommodityTo(){CommodityId=c.CommodityId,CreateDate=c.CreateDate,Name=c.Name,Varies=(从c.Varies中的v选择new VarietyTo())
{
CommodityId=v.CommodityId,Name=v.Name,VarietyId=v.VarietyId
}) };
}
创建一个包含所有数据的ViewModel,然后创建函数填充ViewModel并返回它
查看模型
public class AllStyles
{
public IEnumerable<StyleDTO> Commodities {get;set;}
public IEnumerable<LabelDTO> Labels {get;set;}
public IEnumerable<CommodityDTO> Styles {get;set;}
}
“AllStyles”是这个类更好的名字:)@ssg同意-我想,当我键入答案时,GetAllStyles就卡在我的脑海里了!
[ActionName("StylesAll")]
public AllStyles GetAllStyles()
{
return new AllStyles{
Styles = from s in db.styles
select new StyleDTO() {
Name = s.Name,
StyleId = s.StyleId },
Labels = from l in db.Labels
select new LabelDTO() {
Name = l.Name,
LabelId = l.LabelId ,
image = l.image},
Commodities = from c in db.Commodities
select new CommodityDTO() {
CommodityId = c.CommodityId,
CreateDate = c.CreateDate,
Name = c.Name,
Varieties = ( from v in c.Varieties
select new VarietyDTO() {
CommodityId = v.CommodityId,
Name = v.Name,
VarietyId = v.VarietyId})}
};
}