C# 如何在C语言中连接多服务器和数据库#

这是我的密码

public class MyDatabaseConnection
{
    string connectionString = "Data Source= my DS3;Initial Catalog = MyCATA;Persist Security Info=True;User ID=sa;Password=mypsw*";

    public MyDatabaseConnection(string connectionString)
    {
        this.connectionString = connectionString;
        // create a database connection perhaps
    }

    // some methods for querying a database
    public void execute(string query) { }
}

---

我的目标是当我搜索这个文件名时，它将从不同的服务器搜索整个数据库。示例：如果未找到，它将在服务器1数据库上搜索。如果找到，它将转到下一个服务器2数据库到服务器3数据库。如果找到，它将在datagridview中给出结果。您可以更改表单，如下所示：

public partial class Form1 : Form
{
    public Form1()
    {
        InitializeComponent();
    }

    string connectionString ;

    public void searchOnAllDatabases(string query)
    {

        MyDatabaseConnection con1 = new MyDatabaseConnection("Data Source= 10.232.1.15\\SERVER1;Initial Catalog = My Catalog;Persist Security Info=True;User ID=sa;Password=myPSW");  //----1st search here 
        MyDatabaseConnection con2 = new MyDatabaseConnection("Data Source= 10.232.1.15\\SERVER2;Initial Catalog = My Catalog;Persist Security Info=True;User ID=sa;Password=myPSW");  //---- 2nd search here 
        MyDatabaseConnection con3 = new MyDatabaseConnection("Data Source= 10.232.1.15\\SERVER3;Initial Catalog = My Catalog;Persist Security Info=True;User ID=sa;Password=myPSW");  //---- 3rd search here 

        MyDatabaseConnection[] cons = new MyDatabaseConnection[] { con1, con2, con3 };

        foreach (MyDatabaseConnection con in cons)
        {


            MessageBox.Show(Convert.ToString(cons)); //--to see the result only
        }

    }

您可以在此处更新搜索代码：

public partial class Form1 : Form
{
    public Form1()
    {
        InitializeComponent();
    }


public void searchOnAllDatabases(string query)
{

MyDatabaseConnection con1 = new MyDatabaseConnection("Data Source= 10.232.1.15\\SERVER1;Initial Catalog = My Catalog;Persist Security Info=True;User ID=sa;Password=myPSW");  //----1st search here 
    MyDatabaseConnection con2 = new MyDatabaseConnection("Data Source= 10.232.1.15\\SERVER2;Initial Catalog = My Catalog;Persist Security Info=True;User ID=sa;Password=myPSW");  //---- 2nd search here 
    MyDatabaseConnection con3 = new MyDatabaseConnection("Data Source= 10.232.1.15\\SERVER3;Initial Catalog = My Catalog;Persist Security Info=True;User ID=sa;Password=myPSW");  //---- 3rd search here 

MyDatabaseConnection[] cons = new MyDatabaseConnection[] { con1, con2, con3 };

foreach (MyDatabaseConnection con in cons)
{
    var result = con.execute(query);
    if (result)
       break;
}

 }
}

---

错误是什么？这就是我的意思，先生，我想查询搜索每个服务器和数据库如果在服务器1中没有结果，它将进入服务器2，如果服务器2发现它将不会进入服务器3您将如何确定您已经得到了结果，我的意思是您没有提供搜索代码？public void tloging（）{MyDatabaseConnection myCon=new MyDatabaseConnection（）；SqlConnection sqlCon=new SqlConnection（myCon.MyDTConn）；尝试{sqlCon.Open（）；if（（dtblMonitor==null）| |（dtblMonitor.Rows.Count==0））{MessageBox.Show（“搜索其他数据库”）；Tlogging（）；}基本上，它将在dataGridView结果中显示为我的查询。如果datagrid中没有结果，它将在第一个数据库上搜索，并将移动到其他数据库。你能给我一个代码示例吗。你的代码中的dtblMonitor是什么？我找不到它的声明。

public class MyDatabaseConnection
{

string connectionString = "Data Source= my DS3;Initial Catalog = MyCATA;Persist Security Info=True;User ID=sa;Password=mypsw*";

public MyDatabaseConnection(string connectionString)
{
    this.connectionString = connectionString;
    // create a database connection perhaps
}

    // some methods for querying a database
 public bool execute(string query)
    {
        SqlConnection sqlCon = new SqlConnection(connectionString);
        try
        {
            sqlCon.Open();
            SqlDataAdapter sqlDaMonitor = new SqlDataAdapter("select * from TLogging where BatchNumber like '%" + query + "%' ", sqlCon);
            DataTable dtblMonitor = new DataTable();
            sqlDaMonitor.Fill(dtblMonitor);
            if ((dtblMonitor == null) || (dtblMonitor.Rows.Count == 0)) {
                MessageBox.Show("SEARCH OTHER DATABASE");
                myCon.Val += 1;
                MessageBox.Show(myCon.MyDTConn);

                return false;
            }


        }
        catch(Exception ex)
        {
            return false;
        }
        return true;
    }


}