C# 我是否可以更改弹出窗口的对齐方式,使其显示在按钮的左侧而不是右侧?
关于我如何改变这个职位有什么想法吗?这是菜单: 下面是XAML:C# 我是否可以更改弹出窗口的对齐方式,使其显示在按钮的左侧而不是右侧?,c#,wpf,xaml,popup,togglebutton,C#,Wpf,Xaml,Popup,Togglebutton,关于我如何改变这个职位有什么想法吗?这是菜单: 下面是XAML: <Canvas MinHeight="25" Panel.ZIndex="99"> <ToggleButton x:Name="btnPluginMenu" Content="CT" Width="48" Height="48" Canvas.Left="452" Canvas.Top="263"/> <Popup Placement="Top" PlacementTarget="{Binding
<Canvas MinHeight="25" Panel.ZIndex="99">
<ToggleButton x:Name="btnPluginMenu" Content="CT" Width="48" Height="48" Canvas.Left="452" Canvas.Top="263"/>
<Popup Placement="Top" PlacementTarget="{Binding ElementName=btnPluginMenu}" IsOpen="{Binding ElementName=btnPluginMenu, Path=IsChecked}">
<Grid Background="Gray" Width="175" Height="130">
<Grid.BitmapEffect>
<DropShadowBitmapEffect />
</Grid.BitmapEffect>
</Grid>
</Popup>
</Canvas>
从中,您可以使用Placement=Relative
模式:
弹出控件相对于PlacementTarget左上角的位置,位于由HorizontalOffset和VerticalOffset属性值定义的偏移处。如果屏幕边缘遮挡弹出窗口,控件将重新定位以与屏幕边缘对齐
换句话说,您可以这样做:
<ToggleButton x:Name="btnPluginMenu" Content="CT" Width="48" Height="48" Canvas.Left="452" Canvas.Top="263"/>
<Popup Placement="Relative" HorizontalOffset="-120" VerticalOffset="-130" PlacementTarget="{Binding ElementName=btnPluginMenu}" IsOpen="{Binding ElementName=btnPluginMenu, Path=IsChecked}">
请注意,在单击按钮的事件中,使用了负值
水平偏移
和垂直偏移
private void button_Click(object sender, RoutedEventArgs e)
{
Button button = sender as Button;
popup.PlacementTarget = button;
popup.HorizontalOffset = -120;
popup.VerticalOffset = -130;
popup.IsOpen = true;
}