C# 为什么GetSystemInfo（）.minimumApplicationAddress返回的数字大于GetSystemInfo（）.maximumApplicationAddress？

我正在学习如何操作内存的教程，不管出于什么原因，下面的代码给出了65536表示最小地址，给出了-65537表示最大地址，这没有多大意义

我希望最大地址大于最小地址，否则将意味着没有地址

是一个链接到我下面的教程，以防有帮助

SYSTEM_INFO sys_info = new SYSTEM_INFO();
GetSystemInfo(out sys_info);

IntPtr proc_min_address = sys_info.minimumApplicationAddress;
IntPtr proc_max_address = sys_info.maximumApplicationAddress;

// saving the values as long ints so I won't have to do a lot of casts later

long proc_min_address_l = (long)proc_min_address;
long proc_max_address_l = (long)proc_max_address;

Console.WriteLine("Min Addr: {0}, Max Addr: {1}", proc_min_address_l, proc_max_address_l);

---

sys\u info.maximumApplicationAddress

根据平台类型进行更改：
任何CPU:0xfffeffff
x64:0x00007FFFFFFFF
x86:0x7ffefff

对long执行强制转换时，您正在强制转换0xfffeffff的4字节有符号值（int32），即-65537

由于使用内存地址，因此不会有任何负值，因此可以更改为无符号值。

IntPtr至UIntPtr

龙至乌龙

public struct SYSTEM_INFO
{
...
    public UIntPtr minimumApplicationAddress;
    public UIntPtr maximumApplicationAddress;
...
}

public static void Main()
{
    SYSTEM_INFO sys_info = new SYSTEM_INFO();
    GetSystemInfo(out sys_info);

    UIntPtr proc_min_address = sys_info.minimumApplicationAddress;
    UIntPtr proc_max_address = sys_info.maximumApplicationAddress;

    // saving the values as ulong ints so I won't have to do a lot of casts later

    ulong proc_min_address_l = (ulong)proc_min_address;
    ulong proc_max_address_l = (ulong)proc_max_address;

    Console.WriteLine("Min Addr: {0}, Max Addr: {1}", proc_min_address_l, proc_max_address_l);
}

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我无法重现此问题，最小地址是65536，最大地址是140737488289791这可能是错误还是windows的安全锁？