C# 如何使用XPath获取XML节点的属性值
这是我的脚本,但它只打印控制台中的空格。有人能解释一下如何使用xPath从XML文件中获取属性值吗C# 如何使用XPath获取XML节点的属性值,c#,xml,xpath,C#,Xml,Xpath,这是我的脚本,但它只打印控制台中的空格。有人能解释一下如何使用xPath从XML文件中获取属性值吗 XPathNavigator nav; XPathDocument docNav; XPathNodeIterator NodeIter; XmlNamespaceManager ns; Int32 elementCount; String windowName; private void Form1_Load(object sende
XPathNavigator nav;
XPathDocument docNav;
XPathNodeIterator NodeIter;
XmlNamespaceManager ns;
Int32 elementCount;
String windowName;
private void Form1_Load(object sender, EventArgs e)
{
docNav = new XPathDocument("C:/BlueEyeMacro/DaMaGeX/Applications/WindowBuilder/GUI.xml");
nav = docNav.CreateNavigator();
ns = new XmlNamespaceManager(nav.NameTable);
elementCount = nav.Select("/GUI/window").Count;
Console.WriteLine(elementCount);
for (int i = 1; i <= elementCount; i++)
{
NodeIter = nav.Select("/GUI/window[@ID="+i+"]");
windowName = NodeIter.Current.GetAttribute("name", ns.DefaultNamespace);
Console.WriteLine("{0}", windowName);
}
}
}
XPathNavigator导航;
XPathDocument docNav;
XPathNodeIterator NodeIter;
xmlnamespaces管理器;
Int32元素计数;
字符串窗口名;
私有void Form1\u加载(对象发送方、事件参数e)
{
docNav=new-XPathDocument(“C:/blueyemacro/DaMaGeX/Applications/WindowBuilder/GUI.xml”);
nav=docNav.CreateNavigator();
ns=新的XmlNamespaceManager(nav.NameTable);
elementCount=nav.Select(“/GUI/window”).Count;
控制台写入线(elementCount);
对于(int i=1;i我想,您必须首先调用NodeIter.MoveNext(),就像下面的代码:
XPathNodeIterator nodesText = nodesNavigator.SelectDescendants(XPathNodeType.Text, false);
while (nodesText.MoveNext())
{
Console.Write(nodesText.Current.Name);
Console.WriteLine(nodesText.Current.Value);
}
我想,您必须首先调用NodeIter.MoveNext(),如下面的代码所示:
XPathNodeIterator nodesText = nodesNavigator.SelectDescendants(XPathNodeType.Text, false);
while (nodesText.MoveNext())
{
Console.Write(nodesText.Current.Name);
Console.WriteLine(nodesText.Current.Value);
}
您还可以修改代码以执行此操作:
for (int i = 1; i <= elementCount; i++)
{
var NodeIter = nav.SelectSingleNode("/GUI/window[@ID='"+i+"']/@name"); //This selects the @name attribute directly
Console.WriteLine("{0}", NodeIter.Value);
}
for(int i=1;i您还可以修改代码以执行此操作:
for (int i = 1; i <= elementCount; i++)
{
var NodeIter = nav.SelectSingleNode("/GUI/window[@ID='"+i+"']/@name"); //This selects the @name attribute directly
Console.WriteLine("{0}", NodeIter.Value);
}
for(int i=1;i您可以直接获取属性的字符串值:
for (int i = 1; i <= elementCount; i++)
{
// This obtains the value of the @name attribute directly
string val =
nav.Evaluate("string(/GUI/window[@ID='"+i+"']/@name)") as string;
Console.WriteLine(val);
}
for(int i=1;i您可以直接获取属性的字符串值:
for (int i = 1; i <= elementCount; i++)
{
// This obtains the value of the @name attribute directly
string val =
nav.Evaluate("string(/GUI/window[@ID='"+i+"']/@name)") as string;
Console.WriteLine(val);
}
用于(int i=1;i您的代码看起来很奇怪,因为它可能在WinForm project中使用控制台输出,但在其他方面Select语句是合理的。请描述您遇到的问题。DaMaGeX:您可能对比当前接受的解决方案更短/更简单的解决方案感兴趣。您的代码看起来很奇怪,因为它可能在WinForm project中使用控制台输出,但是否则,Select语句是合理的。请描述您遇到的问题。DaMaGeX:您可能对比当前接受的解决方案更短/更简单的解决方案感兴趣。