C# 如何从窗体前面的backgroundWorker获取流程的每个状态
我有一个简单的基于Windows的应用程序。我用C# 如何从窗体前面的backgroundWorker获取流程的每个状态,c#,winforms,C#,Winforms,我有一个简单的基于Windows的应用程序。我用BackgroundWorker一个接一个地发送邮件。 以下是DoWork事件处理程序代码 private void backgroundWorker1_DoWork(object sender, DoWorkEventArgs e) { MailsSample Mails = e.Argument as MailsSample; string readings = "To : " + Mails.To_EmailsID + "-
BackgroundWorker
一个接一个地发送邮件。
以下是DoWork
事件处理程序代码
private void backgroundWorker1_DoWork(object sender, DoWorkEventArgs e)
{
MailsSample Mails = e.Argument as MailsSample;
string readings = "To : " + Mails.To_EmailsID + "- ";
char[] delimiterChars = { ',' };
string[] Emails = Mails.To_EmailsID.Split(delimiterChars);
for (int i = 0; i < Emails.Length; i++)
{
try
{
SmtpClient smtp = new SmtpClient(Mails.SMTP, Mails.PORT);
MailMessage msg = new MailMessage(Mails.From_Email, Emails[i], Mails.subject, Mails.body);
string mto = null;
smtp.UseDefaultCredentials = true;
smtp.Credentials = new NetworkCredential(Mails.From_Email, Mails.password);
smtp.EnableSsl = true;
msg.IsBodyHtml = true;
msg.Subject = Mails.subject;
//if (textBox1.Text != "")
//{
// Attachment at = new Attachment(textBox1.Text);
// msg.Attachments.Add(at);
//}
msg.Body = Mails.body;
mto = Emails[i];
msg.IsBodyHtml = true;
smtp.Send(msg);
readings += "Sent Successfully.";
}
catch (Exception ex)
{
readings += "Error : " + ex.Message;
}
//Mails.t.AppendText ( Environment.NewLine +readings);
}
e.Result = readings;
}
private void backgroundWorker1\u DoWork(对象发送方,DoWorkEventArgs e)
{
MailsSample Mails=e.参数为MailsSample;
string readings=“To:”+Mails.To_EmailsID+“-”;
char[]delimiterChars={',};
字符串[]Emails=Mails.To_EmailsID.Split(delimiterChars);
对于(int i=0;i
这里是for循环,我想从for循环中获取每个状态,它存储在“readings”变量中。我想一个接一个地从任何文本框中查看前面的单个状态(读数)。
在BackgroundWorker
中是否可能 我得到了答案
(sender as BackgroundWorker).ReportProgress((int)(100.0 / totalSteps * i), null);
void backgroundWorker1_ProgressChanged(object sender, ProgressChangedEventArgs e)
{
progressBar1.Value =(int) e.ProgressPercentage;
}
已为此创建BackgroundWorker.ProgressChanged事件。