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如何从XML检索值到C#wpf listview_C#_Xml_Wpf_Xaml_Listview - Fatal编程技术网

如何从XML检索值到C#wpf listview

如何从XML检索值到C#wpf listview,c#,xml,wpf,xaml,listview,C#,Xml,Wpf,Xaml,Listview,我有这样一个XML: <ConfData> <Person> <AgentInfo> <skillLevels> <SkillLevel> <skillDBID value="101" /> <level value="10" /> </SkillLevel> <SkillLevel&

我有这样一个XML:

<ConfData>
  <Person>
    <AgentInfo>
      <skillLevels>
        <SkillLevel>
          <skillDBID value="101" />
          <level value="10" />
        </SkillLevel>
        <SkillLevel>
          <skillDBID value="103" />
          <level value="10" />
        </SkillLevel>
        <SkillLevel>
          <skillDBID value="106" />
          <level value="10" />
        </SkillLevel>
        <SkillLevel>
          <skillDBID value="110" />
          <level value="10" />
        </SkillLevel>
        <SkillLevel>
          <skillDBID value="111" />
          <level value="10" />
        </SkillLevel>
        <SkillLevel>
          <skillDBID value="112" />
          <level value="10" />
        </SkillLevel>
        <CfgSkillLevel>
          <skillDBID value="113" />
          <level value="0" />
        </CfgSkillLevel>
      </skillLevels>
    </AgentInfo>
   </Person>
</ConfData>

以及listview的my.xaml代码:

<ListView x:Name="AInfoLv">
  <ListView.View>
    <GridView>
      <GridViewColumn x:Name="LabelColumn" Header="Label" Width="100" DisplayMemberBinding="{Binding Path=Label}"/>
      <GridViewColumn x:Name="ValueColumn" Header="Value" Width="130" DisplayMemberBinding="{Binding Path=Value}"/>
    </GridView>
  </ListView.View>
</ListView>


如何检索所有skillDBID值和级别值并在listview中相应地显示它们,这意味着skillDBID值将位于Label列,级别值将位于Value列?

我建议您将xml文件转换为C#中的对象(如Dictionary)然后用xaml绑定对象。

要访问xaml文件中的属性,需要使用@符号

XPath=skillDBID/@value
这个XAML适用于示例XML文件

<Window.Resources>
  <XmlDataProvider Source='ConfData.xml'
                    x:Key='ConfXmlSource'
                    XPath="ConfData" />
</Window.Resources>
<Grid DataContext='{Binding Source={StaticResource ConfXmlSource}}'>

  <ListView x:Name="AInfoLv"
            Grid.ColumnSpan='1'
            ItemsSource='{Binding XPath=/ConfData/Person/AgentInfo/skillLevels/SkillLevel}'>
    <ListView.View>
      <GridView>
        <GridViewColumn x:Name="LabelColumn"
                        Header="Label"
                        Width="100"
                        DisplayMemberBinding="{Binding XPath=skillDBID/@value}" />
        <GridViewColumn x:Name="ValueColumn"
                        Header="Value"
                        Width="130"
                        DisplayMemberBinding="{Binding XPath=level/@value}" />
      </GridView>
    </ListView.View>
  </ListView>

</Grid>
屏幕截图


您对此进行过研究吗?这里有数百个例子……嗨,沃尔特·里彻,谢谢你的解决方案。我可以知道如何将XmlDataProvider源代码从代码传递到.xaml吗?因为我是通过代码中的特定过程来获取xml的。我添加了一个在代码中设置XmlDataProvider.Document属性的示例。
 var provider = new XmlDataProvider();
 var xmlFile = new XmlDocument();
 xmlFile.Load(@"..\..\yourdoc.xml");
 provider.Document = xmlFile;
 provider.XPath = "/ConfData";

 AInfoLv.DataContext = provider;